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- Statics Review. Make sure to draw FBD(s). Given the beam with loading as shown below: A 2 kN/m ILITI PE 5m B f 5m Find: (a) The reactions at A and D (b) The internal shear force at C (c) The internal moment at C 20kN E 5m с + 5m D UMIIdentify the maximum shear and maximum moment. Answers: Vmax = 28.98 kN, Mmax = -85.25 kN-m. Kindly give me the solution of this please.The Channel section is used as a purlin placed on top of trusses with spacing of 4.9 m and slope 1V to 4H. The purling are supporting a total uniform load of 16 kN/m. Properties of Channel:Sx = 119 x 10^3 mm^3Sy = 87 × 10^3 mm^3 Questions:Compute the maximum bending stress if supported by sagrods at midpoint.
- a 6m simply supported beam with ends supports carries a dead load of 25k N/m (excluding its own weight) and a 15k N/m live load , both acting throughout the entire length of the beam. also , two (2) concentrated dead loads 50 kiloNewton and 35 kiloNewton 1.2m apart act where the 50 akiloanewton load is at distance 1m from the left support using the 2010 NSCP factors determine the maximum ultimate shear and maximum ultimate moment on the beam . Present the V and M diagrams. The 0.30 x 0.45m beam weights 23.6 KiloNewton/m3Two d mm*10 mm cover plates are welded to two UPN 200 channels 100 mm high to form the cross section of the compound beam shown in the figure. The moment of inertia of each channel about a horizontal axis through the centroid is 19.10*106 mm4. a) Determine the support reactions. b) Draw the shear force and bending moment diagrams. c) If the allowable bending stress of the beam is 300 MPa, find the required width d of the plates to safely support the load.Maximum Reaction at support A, VA Maximum Reaction at support B, VB Maximum Shear at cutting plane 1-1, V1-1 Maximum Positive and Negative Moments at cutting plane 1-1, M1-1 Maximum Shear at cutting plane 2-2, V2-2 What about if the loading is 10-feet long uniform live load of 640lb/ft? Compute the same functions.
- A simply supported overhang beam is 8.0 m long. It is supported at the right end and at 2.0m from the left end. It carries a 10-kN concentrated load at the left end (0-m), a uniform linear load (4kN/m) from 2-m to 4-m and a 6-kN concentrated load at 6-m. Find the maximum positive shear in kN in whole number and no decimal also no units.Give me the solutions of this. Identity the maximum shear and maximum moment. Answers: Vmax = 28.98 kN, Mmax = -85.25 kN-mFor the given loads F1=42 KN, F2=48 KN, F3=45 KN, F4=32 KN (Assume internal forces are in tension) 1- Magnitude of reaction at K is (KN) :(a. 151 - b. 226.5 - c. 302 - d. 377.5 - e. 453 ) 2- internal force in member JH (KN) :(a. -327 - b. -218 - c. -436 - d. -545 - e. -654) 3- internal force in member IH (KN) : (a. -204.600222 - b. -136.400148 - c. -272.800296 - d. -341.00037 - e. -409.200444 ) 4- Magnitude of reaction at A is (KN) 5- internal force in member IK (KN) is 6- internal force in member GF (KN)
- For the truss below, determine the maximum compressive axial force in member GH due to a concentrated live load of 30 k, a uniformly distributed live load of 2 k/ft, and a uniformly distributed dead load of 1 k/ft.a beam having a width of 300 mm and a depth of 600 mm carries a dead load of 24 kn/m (including its own weight) and a live load of 32 Kn/m. The clear distance between the two supports is 5m. Use 75 mm as steel covering. Use fy=400 Mpa, f’c=21 Mpa. determine: a. maximum shear experience by the beam b. location of the critical shear from the support c. ultimate critical shear occuring on the beamThe steel framework is used to support the 100-mm reinforced stone concrete slab that carries a uniform live loading of 5 kN/m2. Sketch the loading that acts along members BE and FED. Set a = 3m, b = 5m. Hint: See Table 1.2