A. Directions: Give the expected genotypes and phenotypes of the following crosses. Use the Punnett square. a. Two heterozygous purple peas; b. Heterozygous tall and short pea; c. Homozygous round and wrinkled
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The question below, indicate also the genotype and
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- Imagine that you are performing a cross involving seed color in garden pea plants. What traits would you expect to observe in the F1 offspring if you cross true-breeding parents with green seeds and yellow seeds? Yellow seed color is dominant over green. a. only yellow-green seeds b. only yellow seeds c. 1:1 yellow seeds:green seeds d. 1:3 green seeds:yellow seedsSolve the following problem by listing the given genotypes, test crosses, and genotypic and phenotypic ratios. A man who is homozygous for blood type B is married to a woman who is heterozygous for blood type A. Do the test cross and identify the phenotypic and genotypic ratios of their offspring.A heterozygous individual is crossed with a homozygous recessive individual. a. Draw a Punnett square to represent this cross. b. What is the probability that an offspring will have a homozygous genotype? c. What is the probability that an offspring will have a dominant phenotype? d. What is the probability that three offspring will be produced that all carry the recessive allele but do not express the recessive phenotype?
- Questions a to e are answerable by yes or no. Indicate the possible parental genotypes if your answer is yes.a. Can a man with hairy ears have a hairy-eared daughter?b. Can two normal parents produce a colorblind son?c. Can two normal parents produce a colorblind daughter?d. Can a colorblind woman have a normal son?e. Can a bald man have a nonbald daughter?Rabbits may be classified as agouti, chinchilla, Himalayan, or albino according to coat color. A crossbetween CC^h x C^ch c produced 5 agouti, 3 chinchilla and 2 Himalayans. a. What are the phenotypes of the parent rabbits? b. What are the genotypes of the F1s? c. What mode of inheritance is exhibited? d. If the two F1 agouti genotypes will be crossed, what percentage of their offspring will have the same phenotype? e. What will be the genotypes of the rabbits in (d)?solve the cross for dominant epistasis duplicate epistatic resistive epistatic duplicate recessive epistasis table and explanation with phenotype ratio
- Show the results of a monohybrid cross for the F1 and F2 generation between P generation of a woman who is homozygous dominant for unattached ear lobe with a man who is homozygous recessive for attached ear lobe. Clearly show the cross indicating parent’s sex, genotype and phenotype for each generation. How many offspring in the F2 generation will have attached or detached earlobe?A. Consider this cross before answering the following questions:A pea plant heterozygous for the first trait and recessive for the second trait is crossed with a pea plant heterozygous for the first trait and homozygous-dominant for the second trait. 1. If the first gene is demonstrating recessive epistasis to the second gene, what is the probability that the F1 progeny will express a. the dominant feature for the second trait?b. the recessive feature for the second trait?c. neither dominant nor recessive features for the second trait?A- In pea plants, “Tall” is dominant to “Short” and red flower color is dominant to white. Cross a homozygous red, tall plant with a homozygous white, short plant. Give the genotype and phenotypes for F1 and F2 generations. B- In rabbits, black is due to a dominant gene, brown color is recessive. Short hair is dominant and long hair is recessive. Cross a homozygous black, short-haired rabbit with a homozygous brown, long-haired rabbit. Give the genotype and phenotype for F1 and F2 generations.
- Explain the following features of the Mendelian traits and fill the Punnet Squares. a)The disappearance of recessive phenotype in the F1 generation. b)The genotype of an individual expressing dominant phenotype can be differentiated by the test cross.In a certain type of pea plant, the gene for yellow color (Y) is dominant to the gene for green color (y), and the gene for round shape (R) is dominant to the gene for wrinkled shape (r). If a homozygous dominant plant is mated with a homozygous recessive plant (P-gen), what proportion in the F2 generation will be homozygous recessive? a) 1/4 b) 1/16 c) 3/4 d) 3/8Complete the punnet square and indicate the genotype and phenotype of the following monohybrid cross: Black fur is dominant (B) to brown fur (b) in dogs, if the female is heterozygous and the male is recessive, fill out the following Punnett square and provide all the phenotypes and genotypes of their possible puppies.