a. Use synthetic division to show that 2 is a solution of the polynomial equation below. 15x – 10x2 + 12x – 104 = 0 b. Use the solution from part (a) to solve this problem. The number of eggs, f(x), in a female moth is a function of her abdominal width, in millimeters, modeled by the equation below. f(x) = 15x3 – 10x? + 12x – 33 What is the abdominal width when there are 71 eggs? a. The number 2 is a solution to the equation because the remainder of the division, 15x - 10x2 + 12x - 104 divided by x-2, is

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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a. Use synthetic division to show that 2 is a solution of the polynomial equation below.
15x3 - 10x2 + 12x – 104 = 0
b. Use the solution from part (a) to solve this problem. The number of eggs, f(x), in a female moth is a function of her abdominal width, in millimeters, modeled by the equation below.
f(x) = 15x3 – 10x² + 12x – 33
What is the abdominal width when there are 71 eggs?
a. The number 2 is a solution to the equation because the remainder of the division, 15x – 10x + 12x - 104 divided by x- 2, is.
Transcribed Image Text:a. Use synthetic division to show that 2 is a solution of the polynomial equation below. 15x3 - 10x2 + 12x – 104 = 0 b. Use the solution from part (a) to solve this problem. The number of eggs, f(x), in a female moth is a function of her abdominal width, in millimeters, modeled by the equation below. f(x) = 15x3 – 10x² + 12x – 33 What is the abdominal width when there are 71 eggs? a. The number 2 is a solution to the equation because the remainder of the division, 15x – 10x + 12x - 104 divided by x- 2, is.
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