a. Use the Intermediate Value Theorem to show that the following equation has a solution on the given interval. b. Use the graphing utility to find all the solutions to the equation on the given interval. c. llustrate your answers with an appropriate graph. -x + 5x? - 3x = 1: (-1,5) Solution on (-1,5)7

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter9: Polynomial And Rational Functions
Section9.5: Graphing Rational Functions
Problem 36PS
icon
Related questions
Question
Please answer quick! Show all work!
a. Use the Intermediate Value Theorem to show that the following equation has a solution on the given interval.
b. Use the graphing utility to find all the solutions to the equation on the given interval.
c. Illustrate your answers with an appropriate graph.
-x + 5x? - 3x = 1;(- 1,5)
Why can the Intermediate Value Theorem be used to show that the equation has a solution on (-1,5)7
defined at x = -1 and x= 5.
O A. It can be used because f(x) = -x + 5x - 3x is continuous on [- 1,5] and the function
OB.
It can be used because f(x) = - x° + 5x - 3x is defined on (-1,5) and 1<f(- 1) < f(5).
O C. It can be used because f(x) = - x + 5x - 3x is continuous on [- 1,5] and 1 is between f(- 1) and f(5).
O D. It can be used because f(x) = -x + 5x - 3x is defined on (-1,5) and f(- 1)< f(5) <1.
b. There is/are a solution(s) to the equation in (-1,5) at x - 1,5
(Type integer or decimals rounded to three decimal places as needed. Use a comma to separate answers as needed.)
c. Choose the correct graph below. The window setting is given below each graph.
OD.
OC.
OB.
[-2,6,1] by
[-6,10,1]
[-2,6,1] by
[- 20,10,2]
[-2,6,1) by
[-20,10,2]
(-2,6,1] by
[-6,10,1]
Transcribed Image Text:a. Use the Intermediate Value Theorem to show that the following equation has a solution on the given interval. b. Use the graphing utility to find all the solutions to the equation on the given interval. c. Illustrate your answers with an appropriate graph. -x + 5x? - 3x = 1;(- 1,5) Why can the Intermediate Value Theorem be used to show that the equation has a solution on (-1,5)7 defined at x = -1 and x= 5. O A. It can be used because f(x) = -x + 5x - 3x is continuous on [- 1,5] and the function OB. It can be used because f(x) = - x° + 5x - 3x is defined on (-1,5) and 1<f(- 1) < f(5). O C. It can be used because f(x) = - x + 5x - 3x is continuous on [- 1,5] and 1 is between f(- 1) and f(5). O D. It can be used because f(x) = -x + 5x - 3x is defined on (-1,5) and f(- 1)< f(5) <1. b. There is/are a solution(s) to the equation in (-1,5) at x - 1,5 (Type integer or decimals rounded to three decimal places as needed. Use a comma to separate answers as needed.) c. Choose the correct graph below. The window setting is given below each graph. OD. OC. OB. [-2,6,1] by [-6,10,1] [-2,6,1] by [- 20,10,2] [-2,6,1) by [-20,10,2] (-2,6,1] by [-6,10,1]
a. Use the Intermediate Value Theorem to show that the following equation has a solution on the given interval.
b. Use the graphing utility to find all the solutions to the equation on the given interval.
c. Illustrate your answers with an appropriate graph.
x² + 5x? - 3x= 1; (- 1,5)
a. The Intermediate Value Theorem states that if f is continuous on the interval [a,b) and L is a number strictly between f(a) and f(b), then there exists at least one number c in (a.b) satisfying f(c) = L.
For which values of x is the function f(x) = - x° + 5x - 3x continuous?
O A.
It is continuous for all x.
O B. It is continuous for some x, but not on [-1,5].
Oc.
It is continuous on [- 1,5], but not for all x.
O D.
It is not continuous on any interval.
Evaluate the function f(x) at the left endpoint.
The value of the function at the left endpoint is-5
(Type an integer or decimal rounded to three decimal places as needed.)
Evaluate the function f(x) at the right endpoint.
The value of the function at the right endpoint is 1.
(Type an integer or decimal rounded to three decimal places as needed.)
Transcribed Image Text:a. Use the Intermediate Value Theorem to show that the following equation has a solution on the given interval. b. Use the graphing utility to find all the solutions to the equation on the given interval. c. Illustrate your answers with an appropriate graph. x² + 5x? - 3x= 1; (- 1,5) a. The Intermediate Value Theorem states that if f is continuous on the interval [a,b) and L is a number strictly between f(a) and f(b), then there exists at least one number c in (a.b) satisfying f(c) = L. For which values of x is the function f(x) = - x° + 5x - 3x continuous? O A. It is continuous for all x. O B. It is continuous for some x, but not on [-1,5]. Oc. It is continuous on [- 1,5], but not for all x. O D. It is not continuous on any interval. Evaluate the function f(x) at the left endpoint. The value of the function at the left endpoint is-5 (Type an integer or decimal rounded to three decimal places as needed.) Evaluate the function f(x) at the right endpoint. The value of the function at the right endpoint is 1. (Type an integer or decimal rounded to three decimal places as needed.)
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Knowledge Booster
Research Ethics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, advanced-math and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Algebra for College Students
Algebra for College Students
Algebra
ISBN:
9781285195780
Author:
Jerome E. Kaufmann, Karen L. Schwitters
Publisher:
Cengage Learning
Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage
Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
Algebra
ISBN:
9780395977224
Author:
Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:
McDougal Littell