a. Use the Intermediate Value Theorem to show that the following equation has a solution on the given interval. b. Use a graphing utility to find all the solutions to the equation on the given interval. c. Illustrate your answers with an appropriate graph. 2x° +x+2 = 0; (-1,0) ... Why can the Intermediate Value Theorem be used to show that the equation has a solution on (-1,0)? A. It can be used because f(x) = 2x + x+ 2 is defined on (- 1,0) and f(- 1)

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a. Use the Intermediate Value Theorem to show that the following equation has a solution on the given interval.
b. Use a graphing utility to find all the solutions to the equation on the given interval.
c. Illustrate your answers with an appropriate graph.
2x° +x+2=D0; (-1,0)
Why can the Intermediate Value Theorem be used to show that the equation has a solution on (- 1,0)?
3
A. It can be used because f(x) = 2x +x + 2 is defined on (- 1,0) and f(- 1) < f(0) < 0.
%3D
В.
It can be used because f(x) = 2x° + x + 2 is continuous on [- 1,0] and 0 is between f(- 1) and f(0).
.3
O C. It can be used because f(x) = 2x° + x+ 2 is defined on (-1,0) and 0< f(- 1) < f(0).
D.
It can be used because f(x) = 2x° + x + 2 is continuous on [- 1,0] and the function is defined at x = - 1 and x= 0.
b. There is/are a solution(s) to the equation in (- 1,0) at x
(Type an integer or decimal rounded to three decimal places as needed. Use a comma to separate answers as needed.)
c. Choose the correct graph below. The window setting is for each graph is [-2,1,1] by [- 10,10,1].
Transcribed Image Text:a. Use the Intermediate Value Theorem to show that the following equation has a solution on the given interval. b. Use a graphing utility to find all the solutions to the equation on the given interval. c. Illustrate your answers with an appropriate graph. 2x° +x+2=D0; (-1,0) Why can the Intermediate Value Theorem be used to show that the equation has a solution on (- 1,0)? 3 A. It can be used because f(x) = 2x +x + 2 is defined on (- 1,0) and f(- 1) < f(0) < 0. %3D В. It can be used because f(x) = 2x° + x + 2 is continuous on [- 1,0] and 0 is between f(- 1) and f(0). .3 O C. It can be used because f(x) = 2x° + x+ 2 is defined on (-1,0) and 0< f(- 1) < f(0). D. It can be used because f(x) = 2x° + x + 2 is continuous on [- 1,0] and the function is defined at x = - 1 and x= 0. b. There is/are a solution(s) to the equation in (- 1,0) at x (Type an integer or decimal rounded to three decimal places as needed. Use a comma to separate answers as needed.) c. Choose the correct graph below. The window setting is for each graph is [-2,1,1] by [- 10,10,1].
a. Use the Intermediate Value Theorem to show that the following equation has a solution on the given interval.
b. Use a graphing utility to find all the solutions to the equation on the given interval.
c. Illustrate your answers with an appropriate graph.
2x +x+2=D0;(-1,0)
O D. It can be used because f(x) = 2x + x + 2 is continuous on [- 1,0] and the function is defined at x = - 1 and x = 0.
b. There is/are a solution(s) to the equation in (- 1,0) at x
(Type an integer or decimal rounded to three decimal places as needed. Use a comma to separate answers as needed.)
c. Choose the correct graph below. The window setting is for each graph is [ -2,1,1] by [ – 10,10,1].
OA.
В.
С.
OD.
Transcribed Image Text:a. Use the Intermediate Value Theorem to show that the following equation has a solution on the given interval. b. Use a graphing utility to find all the solutions to the equation on the given interval. c. Illustrate your answers with an appropriate graph. 2x +x+2=D0;(-1,0) O D. It can be used because f(x) = 2x + x + 2 is continuous on [- 1,0] and the function is defined at x = - 1 and x = 0. b. There is/are a solution(s) to the equation in (- 1,0) at x (Type an integer or decimal rounded to three decimal places as needed. Use a comma to separate answers as needed.) c. Choose the correct graph below. The window setting is for each graph is [ -2,1,1] by [ – 10,10,1]. OA. В. С. OD.
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