Please escalate, urgent solution needed. Thanks in advance. Accept that (C'[0, 1], || - ||1) is a Banach space, wherec'[0, 1] := {x E C[0, 1] : x'(t) E C[0, 1]} andsup a(t)|+ sup |a'(t)|.te[0,1]te[0,1]Prove that : c'[0, 1] → C[0, 1] is a bounded linear operator with |||| = 1.

Consider the given C10,1:x∈C0,1:x'(t)∈C0,1 and x1=supt∈[0,1]x(t)+supt∈[0,1]x'(t)ddt=1

Accept that (C'[0, 1], || - ||1) is a Banach space, where c'(0, 1] := {x € C[0, 1] : a'(t) E C[0, 1]} and ||||1 = sup a(t)|+ sup a'(t)|. te[0,1] te[0,1] Prove that : c'[0, 1] → C[0, 1] is a bounded linear operator with |||| = 1.

Accept that (C'[0, 1], || - ||1) is a Banach space, where c'(0, 1] := {x € C[0, 1] : a'(t) E C[0, 1]} and ||||1 = sup a(t)|+ sup a'(t)|. te[0,1] te[0,1] Prove that : c'[0, 1] → C[0, 1] is a bounded linear operator with |||| = 1.

Elementary Linear Algebra (MindTap Course List)

8th Edition

ISBN:9781305658004

Author:Ron Larson

Publisher:Ron Larson

Chapter5: Inner Product Spaces

Section5.CR: Review Exercises

Problem 47CR: Find an orthonormal basis for the subspace of Euclidean 3 space below. W={(x1,x2,x3):x1+x2+x3=0}

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Question

Please escalate, urgent solution needed. Thanks in advance.

Accept that (C'[0, 1], || - ||1) is a Banach space, where
c'[0, 1] := {x E C[0, 1] : x'(t) E C[0, 1]} and
sup a(t)|+ sup |a'(t)|.
te[0,1]
te[0,1]
Prove that : c'[0, 1] → C[0, 1] is a bounded linear operator with |||| = 1.

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