According to a web page on the internet, the derivative of a pro derivatives: in other words, (fg)'(x) = f'(x)g'(x)` %3D Let f(x) = 8 x + 7', g(x) = 3 x + 4. f(x) = Preview g'(x) = 3 o Preview 'f(x) g'(x) = 24 o Preview (fg)(x)` = 24x^2+53x+28 %3D Preview (fg)'(x)` = 24x+53 X Preview

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 93E
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n Couse 2021/FA Calculus I (MTH
myopenmath.com/assess2/cid=1260308aid=9014095/full
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According to a web page on the internet, the derivative of a product is the product of the
derivatives: in other words,
"(fg)'(x) = f'(x)g'(x)`
Let `f(x) = 8 x + 7', `g(x) = 3 x + 4`.
'f(x) = ` 8
Preview
`g'(x) = ` 3
Preview
'f(x) g'(x) = `| 24
Preview
(fg)(x)` = 24x^2+53x+28
O Preview
(fg)'(x)`
= 24x+53
X Preview
According to the web page, '(fg)'(x) = f'(x) g'(x)`. Based on your work above (check all that appl
O The derivative of a product is the product of the derivatives
O Type here to search
0耳
SAMSUNO
Transcribed Image Text:M MyOpenMath A Desmos | Graphing Calculator * myClackamas n Couse 2021/FA Calculus I (MTH myopenmath.com/assess2/cid=1260308aid=9014095/full 出 Apps O New Tab O stocked 3 Get a similar question You can retry this question beloW According to a web page on the internet, the derivative of a product is the product of the derivatives: in other words, "(fg)'(x) = f'(x)g'(x)` Let `f(x) = 8 x + 7', `g(x) = 3 x + 4`. 'f(x) = ` 8 Preview `g'(x) = ` 3 Preview 'f(x) g'(x) = `| 24 Preview (fg)(x)` = 24x^2+53x+28 O Preview (fg)'(x)` = 24x+53 X Preview According to the web page, '(fg)'(x) = f'(x) g'(x)`. Based on your work above (check all that appl O The derivative of a product is the product of the derivatives O Type here to search 0耳 SAMSUNO
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