АCTIVITY GIVEN : 2x 2x 1 2х + 3 1 f (x) = 1 –x 8 g(x) = 3(x + + 4 h(x) = 6 a.lim -4 · f (x) d.lim (8 · f(x) – g(x) – 2 · h(x)) | X→2 X→2 b.lim (g(x) – h(x)) e.lim (-2· f(x) + 4 • g(x) + 2 · h(x)) X→2 X→2 c.lim (4 · f (x) + h(x)) .3 f.lim G f(x) + g(x)+ 2· h(x)) X→2 X→2 `2 3

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter3: Polynomial And Rational Functions
Section3.6: Rational Functions
Problem 2E
icon
Related questions
Question

Type exact answer only. No other unnecessary symbols or words. Write DNE if you think the limit does not exist.

D,E,F answer only

АCTIVITY
GIVEN :
2x
+ 4 h(x) =
2x
1
2х +
3
1
f (x) = 1 –x
8
g(x) = 3(x +
a.lim -4 · f (x)
X→2
d.lim (8 · f(x) – g(x) – 2 · h(x))
|
X→2
b.lim (g(x) – h(x))
e.lim (-2· f(x) + 4 • g(x) + 2 · h(x))
X→2
X→2
c.lim (4 · f (x) + h(x))
.3
f.lim G f(x) + g(x)+ 2· h(x))
X→2
X→2 `2
3
Transcribed Image Text:АCTIVITY GIVEN : 2x + 4 h(x) = 2x 1 2х + 3 1 f (x) = 1 –x 8 g(x) = 3(x + a.lim -4 · f (x) X→2 d.lim (8 · f(x) – g(x) – 2 · h(x)) | X→2 b.lim (g(x) – h(x)) e.lim (-2· f(x) + 4 • g(x) + 2 · h(x)) X→2 X→2 c.lim (4 · f (x) + h(x)) .3 f.lim G f(x) + g(x)+ 2· h(x)) X→2 X→2 `2 3
Expert Solution
steps

Step by step

Solved in 4 steps with 4 images

Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
College Algebra
College Algebra
Algebra
ISBN:
9781305115545
Author:
James Stewart, Lothar Redlin, Saleem Watson
Publisher:
Cengage Learning
Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage