Af function is said to have a "fixed point" if there is some point p where f (p) = p. Show that the function f(x) = cos(x) has a fixed point in the interval [0, 5].

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A: For the solution follow the next step.

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Q: 2. Find a function f and a number a such that f(t) -dt = tanx. Give proper reasoning.

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A: Given : Fx = cos2x

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Q: 7 f(x) dt 3

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Q: -2,2] R, then show that the function sin for x 0, f(x) = for x 0, aly continuous.

A: There is no such introduction for the solution.I have explained it within the solution.Please go…

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A: Explanation and solutions is given below.....

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Q: If f(x)=tan x, then show that f(x+y)-f(x) = sec^2x tany/ 1-tanxtany

A: The detailed solution is given below Thank you

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Q: (c) Graph f(x) = sinx, 0≤x≤ 2π and also graph f-¹(x).

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