After applying variation of parameters to y " +y = sec(x), the following equations are obtained c{ (x) sin(x) + c, (x) cos(x) = 0 G (2) cos(x) – c, (æ) sin(æ) = sec(x) - What are c,(x) and c2(x)? С1 (х) — 1 C2 (x) = – tan(x) С1 (х) — х C2 (x) = – In(sin(x)) c1 (x) = In(cos(x)) C2 (x) = x С1 (х) — ӕ c2 (x) = In(cos(x))

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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After applying variation of parameters to y " +y = sec(x), the following
equations are obtained
c{ (x) sin(x) + c, (x) cos(x) = 0
G (2) cos(x) – c, (æ) sin(æ) = sec(x)
-
What are c,(x) and c2(x)?
С1 (х) — 1
C2 (x) = – tan(x)
С1 (х) — х
C2 (x) = – In(sin(x))
c1 (x) = In(cos(x))
C2 (x) = x
С1 (х) — ӕ
c2 (x) = ln(cos(x))
Transcribed Image Text:After applying variation of parameters to y " +y = sec(x), the following equations are obtained c{ (x) sin(x) + c, (x) cos(x) = 0 G (2) cos(x) – c, (æ) sin(æ) = sec(x) - What are c,(x) and c2(x)? С1 (х) — 1 C2 (x) = – tan(x) С1 (х) — х C2 (x) = – In(sin(x)) c1 (x) = In(cos(x)) C2 (x) = x С1 (х) — ӕ c2 (x) = ln(cos(x))
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