After differentiating the last expression we obtain thatC(y)3= sin 3y.Hence, we get-sin 3y1Cos 2x = cwhere c is equal toagain.y3/4c=1/2A=Tt/2integratecos(2x)differentiatesin(2x)1/2exactA=Tt/3y=rt/3

Given that, Cy=13sin3y 1 and after differentiating the last expression, we get…

After differentiating the last expression we obtain that 1 C(y) = sin 3y. Hence, we get 1 1 sin 3y-cos 2 3 2 where c is equal to y 3/4 A=TT/2 1/2 exact y=π/3 again. c=1/2 A=TT/3 -cos2x = c integrate cos(2x) differentiate sin(2x)

After differentiating the last expression we obtain that 1 C(y) = sin 3y. Hence, we get 1 1 sin 3y-cos 2 3 2 where c is equal to y 3/4 A=TT/2 1/2 exact y=π/3 again. c=1/2 A=TT/3 -cos2x = c integrate cos(2x) differentiate sin(2x)

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter7: Analytic Trigonometry

Section7.2: Trigonometric Equations

Problem 75E

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Question

After differentiating the last expression we obtain that
C(y)
3
= sin 3y.
Hence, we get
-sin 3y
1
Cos 2x = c
where c is equal to
again.
y
3/4
c=1/2
A=Tt/2
integrate
cos(2x)
differentiate
sin(2x)
1/2
exact
A=Tt/3
y=rt/3

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