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After working an integration problem for the area formed by two intersecting line functions (8-y) - (y-2)2/3 dy  between -4 and 5 in which I let u subsitition equal the (y-2)2/3 as follows: A = intergration from -4 to 5 (correctly checked) of (8-y) - ( u ) dy  gave an answer that was positive but did not match the book answer of 81/2. My calculation for (dy ) was as follows:  du = (y2 - 4y + 4)/3  dy. Since I am using this problem as a model to my understanding of Briggs Calculus chapter 6.2, 3rd ed., would you give me a step by step solution to this problem to help me understand the nature of my error(s)?

Question

After working an integration problem for the area formed by two intersecting line functions (8-y) - (y-2)2/3 dy  between -4 and 5 in which I let u subsitition equal the (y-2)2/3 as follows: A = intergration from -4 to 5 (correctly checked) of (8-y) - ( u ) dy  gave an answer that was positive but did not match the book answer of 81/2. 

My calculation for (dy ) was as follows:  du = (y2 - 4y + 4)/3  dy. 

Since I am using this problem as a model to my understanding of Briggs Calculus chapter 6.2, 3rd ed., would you give me a step by step solution to this problem to help me understand the nature of my error(s)?

check_circleAnswer
Step 1

The given two intersecting line function is ((8–y)–(y–2)2/3) dy.

Plot the graph of two lines a...

6-
(3,5)
10
12
14
(12, -4)
2
help_outline

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6- (3,5) 10 12 14 (12, -4) 2

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Tagged in

Math

Calculus

Integration

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