Ex 4 (Structures-2016-2017, page 133), 5 3m 3m A 3m 4m (10) (5) 20 KN 3m sta F (10) D (10) B Analyze the structure as shown in Fig. belows Area = ( ) (m², Ib= 100 * 10³ cm²¹, E = 20*10³ kN/cm² Answers in structures lectures : 4m (5) (10) Members CD, BD, DE, EF, DF & CF are truss members' Member AB is a frame member 30.6kn.m (₁7 4219 15.1 KN 120 KN ETABS Answers: R₁ = 15.103 kN; M₁ = 30.61 kN.m, FBD = 4.897 KN 4.9 KN

To close a gate valve it is necessary to exert two forces of 80 lb at opposite sides of a hand wheel 4 ft in diameter. Through an accident the wheel is broken and the valve must be closed by a thrusting bar through a slot in the valve stem and exerting a force 5 ft out from the center. Determine the force required and draw a free-body diagram of the bar. Refer to sample problem 5 to solve this problem.

At room temperature (20°C) a 0.5-mm gap exists between the ends of the rods shown. At what temp will the two rods just touch one another?

Locate the centroid of the volume of the solid shown where a hemesphire of radius r is mounted on top of a right circular cylinder of the same radius and altitude h

1.) A reservoir of glycerin has a mass of 1,200 kg and a volume of 0.952 cu.m. determine the ff. a.) weight of glycerin b.) specific weight of glycerin c.) specific gravity of glycerin 2.) Find the capillary rise in a tube for a water glass interface (teta) = 0° if the tube radius is 1mm and the density is 1000 kg/m³. Surface tension of water is 0.0728 N/m.

Calculate suppprt reaction

The value of P = 90kN

The structural component used for a bridge is shown in the attached image. The length of the beam is 4 m and is simply supported at each end. Neglecting the mass of the beam, calculate the reactions RA and RB at the supports when the beam is in equilibrium. Also, consider the addition of a uniformly distributed load 7 kN/m for the entire length of the beam; recalculate the support reactions at the end and comment on your findings.

Q2)A filament 0.5m long and having a cross-sectional area of 1mm2 was stretched to breaking. If the breaking stress for the filament was found to be 109 Pa, calculate the mass which was hung on the filament to break it. Assuming the filament stretched linearly up to breaking, calculate the amount by which the filament stretched. (Young’s modulus for the material = 6 x 1010 Pa) If the assumption in (b) was justified, what might the material have been? State in one word.

If the body shown is in equilibrium, then which of the following is not a correct set of equilibrium eqation?