An 8KB direct mapped write-back cache is organized as multiple blocks, each of size 32- bytes. The processor generates 32-bit addresses. The cache controller maintains the tag information for each cache block comprising of the following. 1 Valid bit 1 Modified bit As many bits as the minimum needed to identify the memory block mapped in the cache. What is the total size of memory needed at the cache controller to store metadata (tags) for the cache?

An 8KB direct mapped write-back cache is organized as multiple blocks, each of size 32- bytes. The processor generates 32-bit addresses. The cache controller maintains the tag information for each cache block comprising of the following. 1 Valid bit 1 Modified bit As many bits as the minimum needed to identify the memory block mapped in the cache. What is the total size of memory needed at the cache controller to store metadata (tags) for the cache?

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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A byte offset of 2 in an address means that each set in a multiway set associative (or in the directly mapped) cache has 4 bytes per set, per cache line. Keeping this in mind, answer the questions given the following details. A cache is organized as a 4 way set associative cache Each set's cache line consists of 4 words (meaning there are 16 bytes per line, for each set of the cache). Each set individually has one Valid bit, and one Dirty bit, for each line. The tag field of this cache is 8 bits wide. The address is 32 bits wide. Question 1g) If we have a write through cache coherency policy, will either of the above organizations make a difference in the amount of power used to do one write through operation (specifically above this cache layer, in the upper level memory structures to maintain coherency.
A byte offset of 2 in an address means that each set in a multiway set associative (or in the directly mapped) cache has 4 bytes per set, per cache line. Keeping this in mind, answer the questions given the following details. A cache is organized as a 4 way set associative cache Each set's cache line consists of 4 words (meaning there are 16 bytes per line, for each set of the cache). Each set individually has one Valid bit, and one Dirty bit, for each line. The tag field of this cache is 8 bits wide. The address is 32 bits wide.. Question 1c) What is the cache size? (Meaning the number of kilobytes of data being stored in this cache, ignoring the tag, dirty, and valid bits) Question 1d) If this same sized cache (meaning the number of kilobytes of the data part from the question 1c above) is instead organized as a direct-mapped cache, what is the total number of 'memory bit cells needed to design this cache instead (meaning how many bitcells including the tag, dirty, and valid bits?…
A byte offset of 2 in an address means that each set in a multiway set associative (or in the directly mapped) cache has 4 bytes per set, per cache line. Keeping this in mind, answer the questions given the following details. A cache is organized as a 4 way set associative cache Each set's cache line consists of 4 words (meaning there are 16 bytes per line, for each set of the cache). Each set individually has one Valid bit, and one Dirty bit, for each line. The tag field of this cache is 8 bits wide. The address is 32 bits wide. In which of these implementations can LRU be used as a replacement policy?
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For a direct-mapped cache design with a 32-bit address, the following bits of the address areused to access the cache.Tag Index Offset31–10 9–6 5–0a– What is the cache block size (in words)? b – How many entries does the cache have? c – What is the ratio between total bits required for such a cache implementation overthe data storage bits?