An advertising firm has decided to ask 106 customers at each of four local shopping malls if they are willing to take part in a market research survey. At a = 0.01 is there evidence to show that the proportions are not all the same. A В C D Willing 66 68 68 65 Not Willing 40 38 38 41 What are the expected numbers? (round to 3 decimal places) A В C D Willing Not Willing The hypotheses are Но: РА — рв — Рс — pD HA: At least one of the proportions is different. (claim) Since a = 0.01 the critical value is 11.345 The test value is: (round to 3 decimal places) The p-value is (round to 3 decimal places) So the decision is to O reject Ho O do not reject Ho Thus the final conclusion is O There is enough evidence to support the claim that at least one of the proportions is different. O There is enough evidence to reject the claim that at least one of the proportions is different. O There is not enough evidence to reject the claim that at least one of the proportions is different. O There is not enough evidence to support the claim that at least one of the proportions is different.

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter9: Counting And Probability
Section9.3: Binomial Probability
Problem 2E: If a binomial experiment has probability p success, then the probability of failure is...
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An advertising firm has decided to ask 106 customers at each of four local shopping malls if they are willing
to take part in a market research survey. At a = 0.01 is there evidence to show that the proportions are not
all the same.
A
В
C
D
Willing
66
68
68
65
Not Willing
40
38
38
41
What are the expected numbers? (round to 3 decimal places)
A
В
C
D
Willing
Not Willing
The hypotheses are
Но: РА — рв — Рс — pD
HA: At least one of the proportions is different. (claim)
Since a = 0.01 the critical value is 11.345
The test value is:
(round to 3 decimal places)
The p-value is
(round to 3 decimal places)
So the decision is to
reject Ho
O do not reject Ho
Thus the final conclusion is
There is enough evidence to support the claim that at least one of the proportions is different.
There is enough evidence to reject the claim that at least one of the proportions is different.
There is not enough evidence to reject the claim that at least one of the proportions is different.
There is not enough evidence to support the claim that at least one of the proportions is different.
Transcribed Image Text:An advertising firm has decided to ask 106 customers at each of four local shopping malls if they are willing to take part in a market research survey. At a = 0.01 is there evidence to show that the proportions are not all the same. A В C D Willing 66 68 68 65 Not Willing 40 38 38 41 What are the expected numbers? (round to 3 decimal places) A В C D Willing Not Willing The hypotheses are Но: РА — рв — Рс — pD HA: At least one of the proportions is different. (claim) Since a = 0.01 the critical value is 11.345 The test value is: (round to 3 decimal places) The p-value is (round to 3 decimal places) So the decision is to reject Ho O do not reject Ho Thus the final conclusion is There is enough evidence to support the claim that at least one of the proportions is different. There is enough evidence to reject the claim that at least one of the proportions is different. There is not enough evidence to reject the claim that at least one of the proportions is different. There is not enough evidence to support the claim that at least one of the proportions is different.
Expert Solution
Step 1

State the hypotheses.

Probability homework question answer, step 1, image 1

That is, there is no evidence to conclude that the proportions are not all the same.

Probability homework question answer, step 1, image 2

There is evidence to conclude that the proportions are not all the same.

Step 2

Obtain the value of the expected numbers.

The value of the expected numbers is obtained below as follows:

From the information, given that

Probability homework question answer, step 2, image 1

The expected value for the variable Willing and the Variable A is 66.750.

Probability homework question answer, step 2, image 2

The expected value for the variable Willing and the Variable C is 66.750

Probability homework question answer, step 2, image 3

 

Probability homework question answer, step 2, image 4

Probability homework question answer, step 2, image 5

Probability homework question answer, step 2, image 6

 

 

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