An athlete is pulling a tire that weighs 12,000 N. The coefficient of static friction between the tire and the ground is 0.42. If the angle that the rope makes with the horizontal is 24 degrees, what is the magnitude of the force that the woman must exert on the rope to just get the tire to start moving?
An athlete is pulling a tire that weighs 12,000 N. The coefficient of static friction between the tire and the ground is 0.42. If the angle that the rope makes with the horizontal is 24 degrees, what is the magnitude of the force that the woman must exert on the rope to just get the tire to start moving?
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![An athlete is pulling a tire that weighs 12,000 N. The
coefficient of static friction between the tire and the ground
is 0.42. If the angle that the rope makes with the horizontal
is 24 degrees, what is the magnitude of the force that the
woman must exert on the rope to just get the tire to start
moving?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F884f43b4-8171-4218-a1be-74002e0fc817%2F8ce048aa-66ba-44a9-927d-383559f67013%2Fac2jyuf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:An athlete is pulling a tire that weighs 12,000 N. The
coefficient of static friction between the tire and the ground
is 0.42. If the angle that the rope makes with the horizontal
is 24 degrees, what is the magnitude of the force that the
woman must exert on the rope to just get the tire to start
moving?
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