An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass mA travels to the left with a speed of vA. Piece B with mass mBtravels to the right with speed vB. Show the velocity of piece B in terms of mA, mB and VA.
An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass mA travels to the left with a speed of vA. Piece B with mass mBtravels to the right with speed vB. Show the velocity of piece B in terms of mA, mB and VA.
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An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass mA travels to the left with a speed of vA. Piece B with mass mBtravels to the right with speed vB. Show the velocity of piece B in terms of mA, mB and VA.
Solution:
Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so:
pBf + pAf = 0
Substituting the expression for momentum results to
mBv_________ + _________mAv_________ = 0
Deriving the expression for the velocity of piece B results to
v_________=(mA/m_________)vA
Transcribed Image Text:An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with a speed of vA. Piece B with mass mg
travels to the right with speed vB. Show the velocity of piece B in terms of mA, mB and VĄ.
Solution:
Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so:
PBf + PAf = 0
Substituting the expression for momentum results to
mBV
+
mAV
= 0
Deriving the expression for the velocity of piece B results to
V
=(mA/m
VA
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