An elevation must be established on a benchmark on an island that is 2536.98 ft from the nearest benchmark on the island’s shore. The surveyor decides to use a total station that has a stated distance measuring accuracy of (3 mm +3 ppm) and a vertical compensator accurate to within 0.4”. The height of instrument was 5.37 ft with an estimated error of 0.05 ft. The prism height was 6.00 ft with an estimated error of 0.02 ft. The single zenith angle is read as The estimated errors in instrument and target centering are 0.003 ft. If the elevation of the occupied benchmark is 632.27 ft, what is the corrected benchmark elevation on the island? (Assume that the instrument does not correct for Earth curvature and refraction.) What is the estimated error in the computed benchmark elevation if the instrument has a DIN 18723 stated accuracy of +-3"?
An elevation must be established on a benchmark on an island that is 2536.98 ft from the nearest benchmark on the island’s shore. The surveyor decides to use a total station that has a stated distance measuring accuracy of (3 mm +3 ppm) and a vertical compensator accurate to within 0.4”. The height of instrument was 5.37 ft with an estimated error of 0.05 ft. The prism height was 6.00 ft with an estimated error of 0.02 ft. The single zenith angle is read as The estimated errors in instrument and target centering are 0.003 ft. If the elevation of the occupied benchmark is 632.27 ft, what is the corrected benchmark elevation on the island? (Assume that the instrument does not correct for Earth curvature and refraction.)
What is the estimated error in the computed benchmark elevation if the instrument has a DIN 18723 stated accuracy of +-3"?
Step by step
Solved in 2 steps with 2 images
