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An ellipse or hyperbola uses the general form Ax? + Cy + Dx + Ey + F = 0. Solving for 5 unknowns (A, B, C, D, E, F) requires 5 equations, needs 5 points given. But if one of the coefficient is divided out (A or C), then only 4 coefficients remain and only 4 points are needed. x² + Cy + Dx + Ey + F = 0 Given 4 points on a vertical ellipse (-1.366, 0), (0, 2.241), (1, -12), and (4, 2.43). Select the missing coefficients (answers have been rounded to the nearest tenth). x²+ [Select] y + [Select] x + [ Select] ♥ y + [ Select] = 0 >

An ellipse or hyperbola uses the general form Ax? + Cy + Dx + Ey + F = 0. Solving for 5 unknowns (A, B, C, D, E, F) requires 5 equations, needs 5 points given. But if one of the coefficient is divided out (A or C), then only 4 coefficients remain and only 4 points are needed. x² + Cy + Dx + Ey + F = 0 Given 4 points on a vertical ellipse (-1.366, 0), (0, 2.241), (1, -12), and (4, 2.43). Select the missing coefficients (answers have been rounded to the nearest tenth). x²+ [Select] y + [Select] x + [ Select] ♥ y + [ Select] = 0 >

Algebra and Trigonometry (MindTap Course List)
Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter12: Conic Sections
Section12.3: Hyperbolas
Problem 52E
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Question 5 An ellipse or hyperbola uses the general form Ax² + Cy + Dx + Ey + F = 0. Solving for 5 unknowns (A, B, C, D, E, F) requires 5 equations, needs 5 points given. But if one of the coefficients is divided out (A or C), then only 4 coefficients remain and only 4 points are needed. x? + Cy + Dx + Ey + F = 0 Given 4 points on a vertical ellipse (-1.366, 0), (0, 2.241), (1, -12), and (4, 2.43). Select the missing coefficients (answers have been rounded to the nearest tenth). x²+ [ Select ] y + [ Select ] x + [ Select ] y + [ Select] v = 0
Transcribed Image Text:Question 5 An ellipse or hyperbola uses the general form Ax² + Cy + Dx + Ey + F = 0. Solving for 5 unknowns (A, B, C, D, E, F) requires 5 equations, needs 5 points given. But if one of the coefficients is divided out (A or C), then only 4 coefficients remain and only 4 points are needed. x? + Cy + Dx + Ey + F = 0 Given 4 points on a vertical ellipse (-1.366, 0), (0, 2.241), (1, -12), and (4, 2.43). Select the missing coefficients (answers have been rounded to the nearest tenth). x²+ [ Select ] y + [ Select ] x + [ Select ] y + [ Select] v = 0
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