an eltner form a mustache (M) or beard (m). M IS domina RM Rm rM rm RRmm Rrmm Rm Rrmm RRMM RrMm RrMm rm rrMm rrmm From the cross, the phenotypes should be in the ratio: 3:3:1:1 Total observed number- 48
an eltner form a mustache (M) or beard (m). M IS domina RM Rm rM rm RRmm Rrmm Rm Rrmm RRMM RrMm RrMm rm rrMm rrmm From the cross, the phenotypes should be in the ratio: 3:3:1:1 Total observed number- 48
Concepts of Biology
1st Edition
ISBN:9781938168116
Author:Samantha Fowler, Rebecca Roush, James Wise
Publisher:Samantha Fowler, Rebecca Roush, James Wise
Chapter8: Patterns Of Inheritance
Section: Chapter Questions
Problem 2ACQ: Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are...
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Please solve question 5 and letter B
Transcribed Image Text:The pads on cats' feet are either made of rubber (R) or metal (r). R is dominant. Their whiskers
can either form a mustache (M) or beard (m). M is dominant.
RM
Rm
rM
rm
RRMM
RrMm
Rm
RRmm
Rrmm
RrMm
Rrmm
rm
Irmm
From the cross, the phenotypes should be in the ratio: 3:3:1:1
Total observed number= 48
Cat RrMm mates with cat Rrmm (note that the parents' genotypes are NOT identical), and they have kittens:
What fraction do you
"еxpect?"
What # of
Here is what you
kittens do you
"еxpect?"*
|3/8 x48=D18
3/8x 48 = 18
"observe."
Rubber feet/mustache
3/8
14
Rubber feet/beard
3/8
15
Metal feet/mustache
1/8
178x 48 = 6
10
Metal feet/ beard
1/8 x 48 = 6
Hint: The number you expect is based on how many total kittens there were; you'll have to add up all the actual
1/8
kittens in the next column yourself because I didn't do it for you.
a) (4) Fill out the blank columns (2 points each column).
b) (3) What is the Chi Square formula?
X={(Observed Valve-Expected Value)
Expected Value
c) (2) how many degrees of freedom in this case?
df=n(Number of classes)-1
df=4-1
df=3
(5) Perform a Chi-square test on these data, to see if there is likelihood that the R and M genes are linked. What is
your resulting Chi² number? (SHOW WORK, of course)
Probabilities
d) (3) Using the table
below, what is your
interpretation and why?
Explain how you used
the table.
df
0. 95
0.90
0.70
0.50
0.30
0.20
0.10
0.05
0.01
0.001
1
0.004
0.016
0.15
0.46
1.07
1.64
2.71
3.84
6.64
10.83
2.
0.10
0.21
0.71
1.39
2.41
3.22
4.61
5.99
9.21
13.82
3
0.35
0.58
1.42
2.37
3.67
4.64
6.25
7.82
11.35
16.27
4
0.71
1.06
2.20
3.36
4.88
5.90
7.78
9.49
13.28
18.47
1.15
1.61
3.00
4.35
6.06
7.29
9.24
11.07
15.09
20.52
1.64
2.20
3.83
5.35
7.23
8.56
10.65
12.59
16.81
22.46
7
2.17
2.83
4.67
6.35
8.38
9.80
12.02
14.07
18.48
24.32
2.73
3.49
5.53
7.34
9.52
11.03
13.36
15.51
20.09
26.13
3.33
4.17
6.39
8.34
10.66
12.24
14.68
16.92
21.67
27.88
10
3.94
4.87
7.27
9.34
11.78
13.44
15.99
18.31
23.21
29.59
11
4.58
5.58
8.15
10.34
12.90
14.63
17.28
19.68
24.73
31.26
12
5.23
6.30
9.03
11.34
14.01
15.81
18.55
21.03
26.22
32.91
13
5.89
7.04
9.93
12.34
15.12
16.99
19.81
22.36
27.69
34.53
14
6.57
7.79
10.82
13.34
16.22
18.15
21.06
23.69
29.14
36.12
15
7.26
8.55
11.72
14.34
17.32
19.31
22.31
25.00
30.58
37.70
20
10.85
12.44
16.27
19.34
22.78
25.04
28.41
31.41
37.57
45.32
25
14.61
16.47
20.87
24.34
28.17
30.68
34.38
37.65
44.31
52.62
30
18.49
20.60
25.51
29.34
33.53
36.25
40.26
43.77
50.89
59.70
50
34.76
37.69
44.31
49.34
54.72
58.16
63.17
67.51
76.15
86.66
Fail to reject | Reject
at 9.05 level
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