An equal-tangent vertical curve is to be constructed between grades of +3.0% and -0.5% (final). Due to design requirements, the offset at the highest point in the curve should be 2.68 m. What is the length of the curve that meets these design requirements?
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- The data given for a vertical sag curve on a roadway plan and profile sheet are as follows: PVI station @ 32+11.61, PVI elevation =54.18 ft, back tangent gradient g1 =- 4.00 percent, forward tangent gradient g2 = + 7.00 percent, and length of curve L= 600ft. Determine the curve elevations at half-station intervals along the curve, and compute the station and elevation of the lowest point.1. A parabolic curve has an ascending grade of 4% which meets a descending grade of 3% at sta. 1+ 180 whose elevation is at 320 m. Compute the elevation of the PVT(point of vertical tangency) if the length of the curve is 280 mA 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and elevation 450 m. The initial grade is -1% and final grade is +1% b) determine the highest and the lowest points on this vertical curve by using the K-value.
- An easement spiral curve has a design speed of 110 Kph. The radius of the central curve is 365 m with a permissible super elevation of 0.06. Determine the Following: a. Centrifugal acceleration so as not to cause discomfort to the driver in m/sec3. b. Length of the transition curve to limit the centrifugal acceleration. c. Length of the short tangent of the transition curve.A vertical alignment for a single carriageway road consists of a parabolic crest curve connecting a straight-line uphill gradient of +4% with a straightline downhill gradient of -3%. Determine the following: (1) Calculate the vertical offset at the point of intersection of the two tangents at PI (2) Calculate the vertical and horizontal offsets for the highest point on the curve.Assume a design speed of 85km/hr and use the absolute minimum K value for crest curves. Show the complete solution asap.a vertical sag curve has tangent grades of -2.2% and 4.1% if the grade changes uniformly at 0.11% per 20m find the length of the curve in meters
- The allowable side friction factor for horizontal curves with a design speed of 100 km/h is 0.12. (a) What superelevation rate would you use for a curve with a design speed of 100 km/h and a radius of 420 m? Round to the nearest whole percent. (b) A spiral transition curve is used to go from a normal crown slope with 2% cross-slopes to full superelevation for the curve described above. If the maximum difference in grade between the centerline and the edge is 1:200 and the roadway consists of two 3.6 m lanes, what is the minimum length of spiral? Round up to the next integral multiple of 20 m. (c) The station of the TS is 501+00. Draw the superelevation diagram.A vertical summit vertical curve has its PVI at station 14+750 with elevation of 76.30m. The grade of the back tangent is +3.4% and forward tangent of -4.8%. If the length of the curve is 300m. Compute the location of the vertical turning point from the PVI.Compute the elevation of the vertical curve turning point.A blind horizontal curve has a length equivalent to 54 meters. If the design sight distance is equivalent to 67 meters, and the moddle ordinate is equivalent to 8.2 meters, calculate the minimum radius of the curve so it can be classified SAFE.
- An equal-tangent crest vertical curve is designed with a PVI at station 110 + 00 (elevation 927.2 ft) and a PVC at station 107 + 43.3 (elevation 921.55 ft). If the high point is at station 110 + 75.5, what is the design speed of the curve?A 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and elevation 450 m. The initial grade is -5% c) determine the desing speed for this vertical curve( in 10 km/h increments )The sight distance of a sag vertical sag curve equal to 120 meters. if the tangent grades of the curve are -4% and +5%. Compute the length of the curve. Compute the design speed of the vertical sag curve. Compute the minimum radius of the sag vertical curve.