An equation of the straight line normal to surface x2 - y3 + z = 8 at the point P(2, -1, 3) on the surface is given by : 4x - 3y + z = 14 4x -Зу + z%3D 8 4х + 5y - z%3D0 r (t) = (2 + 4t) i + (- 1 - 3t) j + (3 + t) k ,te r %3D r (t) = (- 2 + 4t) i + (1 - 3t) j + (-3 + t) k , te R %3D

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section: Chapter Questions
Problem 39RE
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An equation of the straight line normal to surface x2 - y3 + z = 8 at the
point P(2, -1, 3) on the surface is given by :
4x - 3y + z = 14
4x -Зу + z%3D 8
4x + 5y - z = 0
r (t) = (2 + 4t) i + (- 1 - 3t) j' + (3 + t) k ,te r
%3D
r (t) = (- 2 + 4t) i + (1 - 3t) j + (-3 + t) k ,te r
Transcribed Image Text:An equation of the straight line normal to surface x2 - y3 + z = 8 at the point P(2, -1, 3) on the surface is given by : 4x - 3y + z = 14 4x -Зу + z%3D 8 4x + 5y - z = 0 r (t) = (2 + 4t) i + (- 1 - 3t) j' + (3 + t) k ,te r %3D r (t) = (- 2 + 4t) i + (1 - 3t) j + (-3 + t) k ,te r
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