An inverted cone has a height of 15 mm and a radius of 16 mm. The volume of the inverted cone is decreasing at a rate of 534 cubic mm per second, with the height being held constant. What is the rate of change of the radius, in mm per second, when the radius is 6 mm?
Round your answer to the nearest hundredth. (Do not include any units in your answer.)
Remember that the volume of a cone is V=1/3 πr2 h.
The volume of a cone is V=1/3 πr2 h
The volume of the inverted cone is decreasing at a rate of 534 cubic mm per second, with the height being held constant.
dV / dt = 1/3 πh.d(r2)/dt as h is held constant and hence dh/dt = 0
Fnd the formula for the rate of change of the volume, in mm per second.
To find the rate of change of the radius, in mm per second, when the radius is 6 mm.
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