An Iterator is an object that allows your code to produce the elements in a vector or other container one after the other, exactly once. True False
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- javascript Define a function, myIncludes, that accepts two parameters: an array and a searchValue. myIncludes should return true if the searchValue is an element in the array. Otherwise, myIncludes should return false. example myIncludes([10, 20, 30], 20); // => true myIncludes(['apples', 'bananas', 'citrus'], 'pears'); // => falsestruct remove_from_front_of_vector { // Function takes no parameters, removes the book at the front of a vector, // and returns nothing. void operator()(const Book& unused) { (/// TO-DO (12) ||||| // // // Write the lines of code to remove the book at the front of "my_vector". // // Remember, attempting to remove an element from an empty data structure is // a logic error. Include code to avoid that. //// END-TO-DO (12) /||, } std::vector& my_vector; };What header file must you #include in order to define vector objects?
- #ifndef lab5ExF_h #define lab5ExF_h typedef struct point { char label[10]; double x ; // x coordinate for point in a Cartesian coordinate system double y; // y coordinate for point in a Cartesian coordinate system double z; // z coordinate for point in a Cartesian coordinate system }Point; void reverse (Point *a, int n); /* REQUIRES: Elements a[0] ... a[n-2], a[n-1] exists. * PROMISES: places the existing Point objects in array a, in reverse order. * The new a[0] value is the old a[n-1] value, the new a[1] is the * old a[n-2], etc. */ int search(const Point* struct_array, const char* target, int n); /* REQUIRES: Elements struct-array[0] ... struct_array[n-2], struct_array[n-1] * exists. target points to string to be searched for. * PROMISES: returns the index of the element in the array that contains an * instance of point with a matching label. Otherwise, if there is * no point in the array that its label matches the target-label, * it should return -1. * If there are more than…В.width; } { t = B.type; w = { T.type = C.type; T.width = C.width; } T → B C В > int { B.type = integer; B.width 4; } В — foat { B.type = float; B.width = 8; } { C.type = t; C.width = w; } C - [ num] C1 = array(num. value, C1.type); { C.type C.width = num. value x C1. width; }1. An array is a container that holds a group of values of a 2. Each item in an array is called an 3. Each element is accessed by a numerical 4. The index to the first element of an array is 0 and the index to the last element of the array is the length of the 5. Given the following array declaration, determine which of the three statements below it are true. int [] autoMobile = new int [13]; i. autoMobile[0] is the reference to the first element in the array. ii. autoMobile[13] is the reference to the last element in the array. ii. There are 13 integers in the autoMobile array. 6. In java new is a which is used to allocate memory 7. Declare a one-dimensional array named score of type int that can hold9 values. 8. Declare and initialize a one-dimensional byte array named values of size 10 so that all entries contain 1. 9. Declare and initialize a one-dimensional array to store name of any 3 students. 10. Declare a two-dimensional array named mark of type double that can hold 5x3…
- In C++ Create a function that takes in a vector, triples the size of the vector, sets all the values to random numbers, and returns the vector.Functions with 2D Arrays in Java Write a function named displayElements that takes a two-dimensional array, the size of its rows and columns, then prints every element of a two-dimensional array. Separate every row by a new line and every column by a space. In the main function, call the displayElements function and pass in the required parameters. Output 1 2 3 4 5 6 7 8 9PHP Write a modeMaker function Write a function modeMaker() that forms a closure such that the function it returns can be used with your reduce() function above to find the mode of an array. The mode of an array is the value that appears the most frequently (so in the $arr above, the mode is 5). To do this, you will need an array called $seen that keeps the count of times an element has been examined At the end of the reduce function, the $seen array should look like the following for the $arr above: Array ( [10] => 1 [5] => 3 [3] => 1 [1] => 1 [2] => 1 [7] => 1 ) Note that the closure you generate should always be returning the current mode for what it has seen so far (so it will either be the current mode, or the new element passed in). The following is a start for modeMaker: function modeMaker() { $seen = array(); return function($current, $new) use (&$seen) { // your code that uses $seen goes here }; } $mode =…
- Lotto Program C++Write a program that simulates the Powerball lottery. In Powerball, a ticket is comprised of 5 numbers between 1 and 69 that must be unique, and a Powerball number between 1 and 26. The Powerball does not have to be unique. Hint: You can use an array to represent the 5 unique numbers between 1 and 69, and an integer variable to represent the powerball. The program asks the player if they'd like to select numbers or do a 'quickpick', where the numbers are randomly generated for them. If they opt to select numbers, prompt them to type the numbers in and validate that they are unique (except the powerball), and in the correct range. The program then generates a 'drawing' of 5 unique numbers and a Powerball, and checks it against the user's lotto ticket. It assigns winnings accordingly. Because it is so rare to win the lottery, I suggest hard coding or printing values to when testing the part of the program that assigns winnings.What are the benefits of using a vector over an array?Add each element in origList with the corresponding value in offsetAmount. Print each sum followed by a space. Ex: If origList = {40, 50, 60, 70} and offsetAmount = {5, 7, 3, 0}, print: 45 57 63 70 #include <iostream>#include <vector>using namespace std; int main() {const int NUM_VALS = 4;vector<int> origList(NUM_VALS);vector<int> offsetAmount(NUM_VALS);unsigned int i; for (i = 0; i < origList.size(); ++i) {cin >> origList.at(i);} for (i = 0; i < offsetAmount.size(); ++i) {cin >> offsetAmount.at(i);} cout << endl; return 0;} Please help me with this problem using c++.