An object is moving at a steady slow down until it stops. Cover in the fourth second before the last, a displacement of (31.5m) and cover in the third second (45.5m). Calculate the acceleration, the total displacement, and the total time ??
An object is moving at a steady slow down until it stops. Cover in the fourth second before the last, a displacement of (31.5m) and cover in the third second (45.5m). Calculate the acceleration, the total displacement, and the total time ??
Distance travelled by nth second is given by :
where,
u is the initial velocity
a is the acceleration.
At n=4
equation 1 gives,
According to the question,
Thus,
For n=3 we have,
From 1 we have,
Now subtracting 2 from 3 we have,
Using equation 3 we have,
From equation of kinematics we have,
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance travelled
since the particle stops so v=0
Thus,
Total distance travelled is 231.43 m
Till the fourth second distance covered =
To reach the starting point the particle has to move a distance of 31.5 m.
So total distance travelled till starting point is
Remaining distance to be covered from the starting point is
The displacement is 140.43 m
Step by step
Solved in 5 steps
