An object is thrown upward at a speed of 183 feet per second by a machine from a height of 3 feet off the ground. The height h of the object after t seconds can be found using the equation h = – 16t2 + 183t + 3 When will the height be 73 feet? 11.04 seconds

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A: Consider the given figure

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A: given that.

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A: Graph is below  Both are same graph

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A: We have to use quadratic formula to solve the problem as (-b±√b2 -4ac) /2a

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A:

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A: Given: x2+24x+60=0

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A: Our Aim is to find two integers that make the equation y2=225-(i) true.

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A: SOLUTION-

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A:

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A: Solution ) h(t) = -5t2+60t+2 Differentiate with respect to x  h'(t) = -5 × 2 × t + 60 × 1 + 0  […

Q: The formula h = 60t - 5t² can be used to find the height h, in meters, of an object shot upward with…

A: We have given that h=60t-5t2 can be used to find the height of object shot upward after t seconds.

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A: Substitute h=48 in the given equation Then the given equation becomes 48=-16t2+76t

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A: -6(x+4)+3x=-90 On simplifying the above equation we get ..

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A:

Q: How

A:

Q: Benjamin threw a rock straight up from a cliff that was 84 ft above the water. If the height of the…

A: Given that, the cliff is 84 ft above the water. and   h=−16t2+100t+84

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A: Given: Function for the golf ball as h=-82t-6t+4 when it has been hit from the top of hill, To…

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A: Given: The height of an object thrown upward, h= -16t2 + 64t and h = 64 feet

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A: Height of object

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A:

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A: Hit the water means h=0

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A: detailed solution is given below

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A: topic - quadratic equations