An object of mass m falling near the surface of the earth is retarded by air resistance proportional to its velocity so that, according to Newton's Second Law of Motion, dv m- dt mg – kv, where v=v (t) is the velocity of the object at time t, andg is the acceleration of gravity near the surface of the earth. Assume that the object falls from rest at time t=0, that is v (0) =0. The velocity of the object at time t=m/k is v (m/k) = (1 – e-1) O A. mg k O B. None of these

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
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Chapter6: Vector Spaces
Section6.7: Applications
Problem 18EQ
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The velocity of the object at time t=m/k is v (m/k)=
(1 – e-1)
O A.
mg
k
O B. None of these
Oc (1 – e)
mg
k
-
kg
m (1 – e-1)
D.
kg (1 – e)
O E.
Transcribed Image Text:The velocity of the object at time t=m/k is v (m/k)= (1 – e-1) O A. mg k O B. None of these Oc (1 – e) mg k - kg m (1 – e-1) D. kg (1 – e) O E.
An object of mass m falling near the surface of the earth is retarded by air resistance proportional to
its velocity so that, according to Newton's Second Law of Motion,
dv
m-
mg – kv,
dt
where v=v (t) is the velocity of the object at time t, andg is the acceleration of gravity near the
surface of the earth. Assume that the object falls from rest at time t=0, that is v (0) =0.
The velocity of the object at time t=m/k is v (m/k)=
(1 – e-1)
OA.
mg
k
O B. None of these
Transcribed Image Text:An object of mass m falling near the surface of the earth is retarded by air resistance proportional to its velocity so that, according to Newton's Second Law of Motion, dv m- mg – kv, dt where v=v (t) is the velocity of the object at time t, andg is the acceleration of gravity near the surface of the earth. Assume that the object falls from rest at time t=0, that is v (0) =0. The velocity of the object at time t=m/k is v (m/k)= (1 – e-1) OA. mg k O B. None of these
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