An unsymmetrical flexural member consists of a ½ x 12 top flange, a ½ x 7 bottom flange, and a 3/8 x 16 web.b.) If A572 Grade 50 is used, what is the plastic moment Mp for the horizontal plastic neutral axis (already answered)QUESTION: SHOW THE SOLUTION FOR GETTING THE y for the top and bottom flange and the web. NOT THE ȳ . and draw the figure for better understanding. SOLVE THE CIRCLED RED PARTS OF THE IMAGE. 5.2-2(a) Area above PNA = Area below PNA12(1/2) + (-1/2)(3/8) = (1/2+16 − ÿ)(3/8) + 7(1/2)ỹ = 5.17 in.(b) To locate centroids of areas, take moments about plastic neutral axis. For area abovePNA,Componenttop flwebSumA6.0001.7507.750y4.9172.334y = 5.167Ay29.504.08533.59 1=ΣΑΥ 33.59ΣΑ7.750For area below PNA,www.w* 4. 334 in.Componentbot. flwebSum64.617.75052ΣΑyΣΑPlastic moment:Mp = Cx moment arm Tx moment arm= AF,G1 + 72) = 7.750(50)(4.334 + 8.337)A3.5004.2507.750=y11.585.6678. 337 in.wwwww= 387.5(12.67) = 4910 in-kips = 409 ft-kipsAy40.5324.0864.61My = 409 ft-kips

Size of top flange = 1/2" x 12"Size of bottom flange = 1/2" x 7"Size of web =3/8" x 16"

Answered: An unsymmetrical flexural member…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Question

An unsymmetrical flexural member consists of a ½ x 12 top flange, a ½ x 7 bottom flange, and a 3/8 x 16 web.

b.) If A572 Grade 50 is used, what is the plastic moment Mp for the horizontal plastic neutral axis (already answered)

QUESTION: SHOW THE SOLUTION FOR GETTING THE y for the top and bottom flange and the web. NOT THE ȳ . and draw the figure for better understanding. SOLVE THE CIRCLED RED PARTS OF THE IMAGE.

5.2-2
(a) Area above PNA = Area below PNA
12(1/2) + (-1/2)(3/8) = (1/2+16 − ÿ)(3/8) + 7(1/2)
ỹ = 5.17 in.
(b) To locate centroids of areas, take moments about plastic neutral axis. For area above
PNA,
Component
top fl
web
Sum
A
6.000
1.750
7.750
y
4.917
2.334
y = 5.167
Ay
29.50
4.085
33.59

1
=
ΣΑΥ 33.59
ΣΑ
7.750
For area below PNA,
www.w
* 4. 334 in.
Component
bot. fl
web
Sum
64.61
7.750
52
ΣΑy
ΣΑ
Plastic moment:
Mp = Cx moment arm Tx moment arm
= AF,G1 + 72) = 7.750(50)(4.334 + 8.337)
A
3.500
4.250
7.750
=
y
11.58
5.667
8. 337 in.
wwwww
= 387.5(12.67) = 4910 in-kips = 409 ft-kips
Ay
40.53
24.08
64.61
My = 409 ft-kips

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 4 steps with 5 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions