Analyse the IPv4 addresses shown in the below on the left column. Identify the type of each address/prefix pair on the right. 4
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![Analyse the IPv4 addresses shown in the below on the left column.
Identify the type of each address/prefix pair on the right.
123.45.165.255/22
192.168.33.63/25
239.192.1.100/24
10.255.0.0/14
172.16.128.48/27
[Choose ]
[Choose ]
Multicast Address
[Choose ]
[Choose ]
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- What does the "slash-decimal" notation (for example, 1090:9:900:210D:100:100:227:32F / 60) that can follow an IPv6 address denote? (choose one) a number of bits in the network portion of the address b. number of bits in the subnet mask portion of the address c. number of bits in the host portion of the address d. number of bits in the multicast scope identifierWhat must be done with the host part of an IPv6 address? For example, the host part of an IPv6 address is found at.ICMP is used for addressing error reporting routing forwarding Which of the following is an example of a private IP address? 12.127.18 65.20.10 169.200.224 100.20.2 ARP provides a mapping between IP addresses and MAC Addresses Domain Names Phone Numbers Network Addresses
- Subject - Data communication networks How can you write the following IPv4 address 192.168.10.2 in IPv6 format? A network on the Internet has a subnet mask of 255.255.248.0. What is the maximum number of hosts it can handle? Explain two problems of SMTP. Thank you in advance!Is it possible to identify the difference between an IP address and a hostname? How many bits and bytes does a MAC address have? How many bits does an IPv4 address have?IP Address is 69.67.214.64/26 Subnet Mask: Maximum usable hosts: Network Address: Broadcast Address: IP Address is 10.9.3.255/21 Subnet Mask: Maximum usable hosts: Network Address: Broadcast Address: Subnet 192.168.3.0/25 into 7 subnetworks (show working) How many subnets can you get for 27 hosts from 172.16.3.0/26 (show working) Subnet 192.168.1.0/24 into 6 subnetworks but there is a requirement that only the first subnetwork needs to have at least 58 hosts (show working)
- Consider the following non-default subnet masks: (a) 255.255.248.0, (b) 255.128.0.0 . To which IP address class do they pertain?Write down the following in CIDR notation: (a) IP: 150.160.170.180, Subnet Mask:255.255.224.0; (b) IP: 75.80.85.90, Subnet Mask: 255.252.0.0 Three stations A, B, C and D are connected to a common Ethernet hub. Their IPaddresses and subnet mask are respectively: 200.100.50.67, 255.255.255.252;200.100.50.7, 255.255.255.248; 200.100.50.138, 255.255.255.240 and 200.100.50.1,255.255.255.254. Determine which among these stations can communicate with eachother. You need to show all detailed workings.Question 4. IPv6 has three main address types. Using the example of a host sending packets to zero or more interfaces, describe how each address type works.If a class B IP address has the subnet mask 255.255.248.0 then How many maximum host will be possible in the network?
- 1. What is the purpose of an IP address mask? Suppose an IP address isidentified as 200.60.40.88/24. What is the network address in this case?What is the host address? How many hosts can this network addresssupport? Repeat this exercise for the IP address 222.66.44.80/26.2. Explain the concept of a DHCP lease. How is it obtained? How is itused? What does it provide?3. Explain the operation of the Address Resolution Protocol.4. Explain the relationship between corresponding layers at the sourceand destination nodes of a TCP/IP communication connection.Consider the IP address : 157.110.88.0. We need 30 subnets in such a way that each subnet may host up to 64 hosts. i) This address is of which type? ii) How many bits will be required for subnet ID? iii) How many usable subnets will be there? iv) What will be the subnet mask? v) What will be the address of 47th host of 25th subnet?What is the purpose of an IP address mask? Suppose an IP address is identified as 200.60.40.88/24. What is the network address in this case? What is the host address? How many hosts can this network address support? Repeat this exercise for the IP address 222.66.44.80/26.