Analyze and determine the outputs of the following program statements:#include #include int main()(float a-3, c-4,"p, "q;int i, j, k,n-3, b=3,w=2;float x[3][4]=(9,8,1,2,3,4,5,6,7,8,9,10), z[4][3];float y[4]-(1,2,3,4);for(i=0;i<4;i++){ for(j=0;j<3; j++)z[2][1]-x[2][1];q=&z[2][1];printf("*q= %.2f\n", *q*2);for(i=0;i<3; ++i){c+=y[1] -1;z[j][i]=x[i][j];if(w<18)(p=&n;p+=1;}printf("a-%0.2f\n c-%8.2f\n z[2][1] -%0.2f \n",a,c,z[2][1]);i=4;j-3;k-n-1;if (il-jj-3)(1=k;j=j+1;}else if(i<8)(w=n+1+1+1+y[j]; w=n+a+k+2+y[1];}}else(a+=y[i]+b;printf("w-%d",w+5);}printf("w-%d\n",w-5);}

Analyze and determine the outputs of the following program statements: #include #include int main() ( float a-3, c4,"p, "q; int i,j,k,n-3, b-3,w-2; float x[3] [4]-(9,8,1,2,3,4,5,6,7,8,9,10), z[4][3]; float y[4]-(1,2,3,4); for(i=0;i<4;i++) { for(j=0; j<3; j++) } z[2][1][2][1]; q=&z[2][1]; printf("q= %.2f\n", *q*2); for(i=0;i<3;++1) (c+ay[1] -1; z[1][1][1][1]; if(w<10) (p-&n; p+=; } printf("a-%0.2f\n c-%0.2f\n z[2][1]-%0.2f \n", a,c,z[2][1]); 1-4;j-3;k-n-1; if (il-jj-3) (1=k;=j+1;) else if(i<8) (wen+1+1+1+y[1]; wen+a+k+2+y[1];} ) else ( } a+my[1]+b; printf("w-%d",w+5); printf("w-%d\n",w-5);}

Analyze and determine the outputs of the following program statements: #include #include int main() ( float a-3, c4,"p, "q; int i,j,k,n-3, b-3,w-2; float x[3] [4]-(9,8,1,2,3,4,5,6,7,8,9,10), z[4][3]; float y[4]-(1,2,3,4); for(i=0;i<4;i++) { for(j=0; j<3; j++) } z[2][1][2][1]; q=&z[2][1]; printf("q= %.2f\n", q2); for(i=0;i<3;++1) (c+ay[1] -1; z[1][1][1][1]; if(w<10) (p-&n; p+=; } printf("a-%0.2f\n c-%0.2f\n z[2][1]-%0.2f \n", a,c,z[2][1]); 1-4;j-3;k-n-1; if (il-jj-3) (1=k;=j+1;) else if(i<8) (wen+1+1+1+y[1]; wen+a+k+2+y[1];} ) else ( } a+my[1]+b; printf("w-%d",w+5); printf("w-%d\n",w-5);}

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter2: Problem Solving Using C++using

Section2.3: Data Types

Problem 9E: (Practice) Although the total number of bytes varies from computer to computer, memory sizes of...

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(Practice) Although the total number of bytes varies from computer to computer, memory sizes of millions and billions of bytes are common. In computer language, the letter M representsthe number 1,048,576, which is 2 raised to the 20th power, and G represents 1,073,741,824, which is 2 raised to the 30th power. Therefore, a memory size of 4 MB is really 4 times 1,048,576 (4,194,304 bytes), and a memory size of 2 GB is really 2 times 1,073,741,824 (2,147,483,648 bytes). Using this information, calculate the actual number of bytes in the following: a. A memory containing 512 MB b. A memory consisting of 512 MB words, where each word consists of 2 bytes c. A memory consisting of 512 MB words, where each word consists of 4 bytes d. A thumb drive that specifies 2 GB e. A disk that specifies 4 GB f. A disk that specifies 8 GB
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