Analyze and draw the axial, shear, moment diagram and qualitative deflection of each frame. 1. 2 k/ft 30 k E C D Hinge 20 A B 15 ft 15 ft-
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THEORY OF STRUCTURE (Analysis of Statically Determinate Frames)
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- Draw the shear and bending momentdiagrams and the qualitative deflected shape for the beamshown.Compute the slope at point A and deflection at point C of the beam using moment-area method. If L = 6ft, w= 1.5k/ft, I=76.8 in4, and E= 29,000 ksi.Using Moment-Area Method, determine the slope at A and B and the deflection at point B of the loaded beam shown. Use E = 150 GPa and I = 110x106 mm4. (Please show moment diagrams by parts)
- Given (Refer to the pictures): Shear and moment diagram of B2 Requirement: What is the deflection of B2 based on the given references? (KINDLY USE AREA-MOMENT METHOD)find the deflection for B2 (point C TO F) using AMM (Area Moment Diagram)(a) Compute the vertical deflection at C, the horizontal deflection at D and the rotation at A by the virtual work method. (b) If support E moves to the right by 5mm and settles downward by 10mm, compute the additional horizontal deflection at D. Given E=200GPa and I=108mm4 .
- Compute the total net deflection of the simply-supported beam with the following properties listed below. (Include the sign if it is negative) Properties:Length = 11.46 mWidth = 302 mmDepth = 435 mmeccentricity = 96 mmEc = 14,368.22 MPaPrestressing Force = 461 kNUnit weight of concrete = 23.16 kN/m3El-ConstantAnalyze the beam using Moment Distribution MethodDraw shear, bending moment and elastic diagramsDetermine the slope and deflection at point B of the beam shown if the figure. Let e= 29 106 ??? and i= 800??4
- Find the end moments for the continuous beam shown using Moment Distribution Method E= 15GPA Diameter of circle= 300mm I at AB= 2 I at BC= 3 I at CD= 4Tabulate the value of deflection of the beam at an interval of 0.2m from the left support and using this values draw the elastic curve of the beam.Determine the deflection at point C. Use the following parameters: P = 40 kips, w = 3.7 kips/ft, E = 29000 ksi, I = 2700 in4 Answer: -0.664