any produel defective computers that must be rejected tends to increase as the daily output creases. The number of rejects r depends on the total daily output, x, according to the uation: /(x) = - 60x -, for x≤ 180 where 180 is the maximum possible output. Each 250-x mputer produced is either sold or rejected. The company makes a profit of $300 for ch computer sold but loses $100 for each one rejected. What is the profit if they produce the maximum number of computers? What output will maximize the profit?

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter12: Algebra Of Matrices
Section12.CR: Review Problem Set
Problem 37CR
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10) A company is producing Netbook computers. In this manufacturing process, the number
of defective computers that must be rejected tends to increase as the daily output
increases. The number of rejects r depends on the total daily output, x, according to the
60x
equation: 7(x) = -
-, for x≤ 180 where 180 is the maximum possible output. Each
250-x'
computer produced is either sold or rejected. The company makes a profit of $300 for
each computer sold but loses $100 for each one rejected.
a) What is the profit if they produce the maximum number of computers?
b) What output will maximize the profit?
Transcribed Image Text:10) A company is producing Netbook computers. In this manufacturing process, the number of defective computers that must be rejected tends to increase as the daily output increases. The number of rejects r depends on the total daily output, x, according to the 60x equation: 7(x) = - -, for x≤ 180 where 180 is the maximum possible output. Each 250-x' computer produced is either sold or rejected. The company makes a profit of $300 for each computer sold but loses $100 for each one rejected. a) What is the profit if they produce the maximum number of computers? b) What output will maximize the profit?
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