Apply Fourier transform, jw F(w) = F₁ (w) + F₂ (w)...... equation 2 |F₁(t) = −8(t + 2) + 6(t-2)........ equation 3 now t replace by w, ejw te-jw F₁(w) = -2 2 سلام F₁(w) = -4 1(w) = 4jwSin²w. and -e 2 x 2 How did he get the value inside the circle

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.6: Additional Trigonometric Graphs
Problem 78E
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Apply Fourier transform,
|jw F(w) = F₁ (w) + F₂(w)...... equation 2
F₁ (t) = −8(t + 2) + d(t− 2)........ equation 3
now t replace by w,
eju te jw
F₁(w) = -2[+]x2
F₁ (w) = -4 [ee]
2
1₁(w) = 4jwSin²w.
and
How did he get the
value inside the circle
Transcribed Image Text:Apply Fourier transform, |jw F(w) = F₁ (w) + F₂(w)...... equation 2 F₁ (t) = −8(t + 2) + d(t− 2)........ equation 3 now t replace by w, eju te jw F₁(w) = -2[+]x2 F₁ (w) = -4 [ee] 2 1₁(w) = 4jwSin²w. and How did he get the value inside the circle
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