Applying Gauss -Jordan method solve the LSE: Xị + 2x2 – x3 – 2x4 = 3, xị + 2x2 – x3 – 2x4 = 1, %3D 2x1 + x2 + x3 – 4x4 = -1,

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section9.1: Systems Of Equations
Problem 36E
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1. Applying Gauss -Jordan method solve the LSE:
Xị + 2x2 – x3 – 2x4 = 3,
|
x1 + 2x2 – x3 – 2x4 = 1,
|
|
2x1 + x2 + x3 – 4.x4 = -1,
%3D
Transcribed Image Text:1. Applying Gauss -Jordan method solve the LSE: Xị + 2x2 – x3 – 2x4 = 3, | x1 + 2x2 – x3 – 2x4 = 1, | | 2x1 + x2 + x3 – 4.x4 = -1, %3D
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