Bisection Method HOMEWORK 1: O Approximate the root of f(x) =x³ - 3 with the bisection method starting with the interval [1, 2]. Answer: 1.4375 %3D ® Approximate the root of f(x) = x² - 10 with the bisection method starting with the interval [3, 4]. Answer: 3.15625 O Solve x - 9x+1 for roots between x=2 and x=4. Answer: 2.9453 O Solve 2x - cos(x) - x exp(x) for roots between x=1 and x=2. Answer: 1.151855 O Solve 3x=V1+ sinx for roots between x=0 and x=1. Answer: 0.391846

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter5: Exponential And Logarithmic Functions
Section5.4: Exponential And Logarithmic Equations
Problem 83E: The number N of beavers in a given area after x years can be approximated by N=5.5100.23x,0x10. Use...
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Bisection Method
HOMEWORK 1:
O Approximate the root of f(x) =x³ - 3 with the bisection method
starting with the interval [1, 2].
Answer: 1.4375
%3D
© Approximate the root of f(x) = x² - 10 with the bisection
method starting with the interval [3, 4].
Answer: 3.15625
O Solve x - 9x+1 for roots between x=2 and x=4.
Answer: 2.9453
O Solve 2x - cos(x) - x exp(x) for roots between x=1 and x=2.
Answer: 1.151855
O Solve 3x=/1+ sinx for roots between x=0 and x=1.
Answer: 0.391846
Transcribed Image Text:Bisection Method HOMEWORK 1: O Approximate the root of f(x) =x³ - 3 with the bisection method starting with the interval [1, 2]. Answer: 1.4375 %3D © Approximate the root of f(x) = x² - 10 with the bisection method starting with the interval [3, 4]. Answer: 3.15625 O Solve x - 9x+1 for roots between x=2 and x=4. Answer: 2.9453 O Solve 2x - cos(x) - x exp(x) for roots between x=1 and x=2. Answer: 1.151855 O Solve 3x=/1+ sinx for roots between x=0 and x=1. Answer: 0.391846
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