Arcsinx - sinx (1-cos 2 sin 2x Lim

Q: sin(2x) lim x→0 sin(7x)

A: This is infinity/infinity form, apply L-Hospital rule to proceed further.

Q: sin 3x (c) Prove the value of lim Do NOT use L'Hospital's Rule. 0 COS 4x

A: To determine the value of function on the given limit.

Q: Find the limits

A:

Q: Find the limit

A: Consider the limit, First of all, apply the fraction rule, Then,

Q: lim cos(@) - 1 sin(@)

A:

Q: sin 5x 6. lim x→0 sin 10x

A:

Q: find the given limits

A: The given limits,

Q: lim 0→0 sin²0

A: here we have to find the A=limθ→0θsin2θ

Q: sin2x(1-сos2х) 7. lim X→0 (Arcsinx)-sinx

A: Given function is, Finding the limit, This is an indeterminant form. So, use the L'Hopital's rule.

Q: Evaluate the given

A: We will use the below rule, So,

Q: sin x 1 lim

A: To prove, limx→0sin xx=1

Q: tan lim x+1- cos-l x

A:

Q: sin(x-3) 1. lim x→3 x²-4x+3 sin2x 2. lim x→n sin3x cos4x-cos2x 3. lim x→0_arcsin²3x

A:

Q: sin2x(1-cos2x) lim X→0 (Arcsinx)-sinx

A: Definition and methods help to find the required limit of the given function. A value is said to be…

Q: sin 5x lim X→0 sin 4x

A: To find the limit: limx→0sin5xsin4x Solution: Quotient rule of differentiation states that:…

Q: lim 3X Sin 13

A: This is of indeterminate form.

Q: cos(x) +1-sin(x) lim

A:

Q: Find the limits

A:

Q: sin6x 3 - lim 0 sin2x O 1/3 O 1/2

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: lim x→0 (sin 4x/ sin 6x)

A:

Q: Find the limit

A: Recall:

Q: sin TX Q.3 Find the lim, 0 sin 3x

A: the given limit is: limx→0sinπxsin3x we have to evaluate the given limit.

Q: sin3x lim x-1 sin5x

A: here we put x=1  than we get  =sin3.1cos5.1

Q: lim sin (0 + sin(0))

A: limθ→πsinθ+sinθ

Q: sin 5x f. lim

A:

Q: sin(4x) g) lim

A:

Q: tan x - X 1. lim sinx 5 A. 2 В. 2 С. О D. undefined

A:

Q: sin(x) x0 sin(2x) Calculate lim

A:

Q: Lim sin 5A Sin3X

A: From the given problem:   limx→0sin5xsin3x   So,…

Q: sin 2x Find lim 3x

A: given equation     limx--> 0    sin(2x)/3x   ** L hospital rule :-   limx-->0  f(x) / g(x) =…

Q: sinx (1-cosx) 10. Evaluate the lim 2x2 A. -1 В. О C. 1 D. e

A: It is given that, limx→0sinx(1-cosx)2x2 But here as you can see that if you plug in x=0 in the given…

Q: i) lim 5 sin x %3D

A:

Q: sin 4x 18) lim X-0 tan 5x

A:

Q: Arcsinx-sinx 1. lim x→0 (1-cos2x)sin2x 2-2cosx-xln(1+x) 2. lim x→0 x sin² x

A: 1)

Q: sin[arcsin(1)] = -1 1 sin 1

A: We know, sin[arcsin(x)]=x

Q: lim (sin() + cos (+))* x →∞

A: We have to find value of given Limit.

Q: 6. lim (sinx)*

A: u =eln u, then:limx→0+  (sin x)x  =limx→0+  ex ln(sinx)=limx→0+  eln(sinx)1x=elimx→0+  ln sin(x)1x

Q: lim 1-cosx/sinx ? x-->0

A: Given:

Q: sin 0 (1) Lim %3D

A:

Q: lim * 0 sin5x'

A:

Q: sin 3x 39.lim tan 6t 41. lim 50 sin 21

A: We will use the l'hospital rule to fine the limit of 39.  To fine limit 41. We will use the basic…

Q: 'sin 2x 18. lim X-\ sinx в 2 со R-2

A:

Q: evaluate the limit.

A:

Q: sin(4.x) Find lim 1-0 tan(2x)

A:

Q: sin4x 15. lim x→0 sin7x

A:

Q: 11. lim sin x 12. lim sin x 13. lim sin( (x-

A: 11. Consider the given limit limx→3π2sinx and apply the limit x→3π2.…

Q: Sin lim 3xコ スー

A: We have to find limit