are ² de = N(f) df 4 по- 8 N(f) of : tra³f دے > df p=24² fa P=

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter8: Polynomials
Section8.3: Multiplying Polynomials
Problem 54PFA
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May I ask for the steps so that I could get the answer, N(f)df = 4πa^3f^2/c^3 ?

2
and the
8 dp = N(f) df
N(f) # = 4a²f²" df
of
of
па
دے
p=242
afa
Transcribed Image Text:2 and the 8 dp = N(f) df N(f) # = 4a²f²" df of of па دے p=242 afa
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why dp equals to d/df (2fa/c) df?

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