Area = 2 Area = 1. Area = 3 3 5 7 Area = 7 Graph of f' The figure above shows the graph of f', the derivative of a differentiable function f, on the closed interval 0 < x < 7. The areas of the regions between the graph of f' and the x- axis are labeled in the figure. The function f is defined for all real numbers and satisfies ƒ (4) = 10. Let be the function defined by g (x) = 5 – x2.

Trigonometry (MindTap Course List)
10th Edition
ISBN:9781337278461
Author:Ron Larson
Publisher:Ron Larson
ChapterP: Prerequisites
Section: Chapter Questions
Problem 8PS
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Question
(a) Find the value of
I f' (x) dx.
(b) Given that f (4) = 10, write an expression for f (x)
that involves an integral. Use this expression to find the
absolute minimum value of fand the absolute maximum
value of fon the closed interval 0 < x < 7. Justify your
answers.
| 9 (2) da.
g (x)
(c) Find
(d) Find the value of
x f' (g (x)) dæ.
1
Transcribed Image Text:(a) Find the value of I f' (x) dx. (b) Given that f (4) = 10, write an expression for f (x) that involves an integral. Use this expression to find the absolute minimum value of fand the absolute maximum value of fon the closed interval 0 < x < 7. Justify your answers. | 9 (2) da. g (x) (c) Find (d) Find the value of x f' (g (x)) dæ. 1
Area = 2
Area = 1.
Area = 3
3
5
7
Area = 7
Graph of f'
The figure above shows the graph of f', the derivative of a
differentiable function f, on the closed interval 0 < x < 7.
The areas of the regions between the graph of f' and the x-
axis are labeled in the figure. The function ƒ is defined for all
real numbers and satisfies ƒ (4) = 10.
Let
be the function defined by g (x) = 5 – x².
Transcribed Image Text:Area = 2 Area = 1. Area = 3 3 5 7 Area = 7 Graph of f' The figure above shows the graph of f', the derivative of a differentiable function f, on the closed interval 0 < x < 7. The areas of the regions between the graph of f' and the x- axis are labeled in the figure. The function ƒ is defined for all real numbers and satisfies ƒ (4) = 10. Let be the function defined by g (x) = 5 – x².
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