ARGUMENT SEVEN Valid D / Invalid O 1. R (T v S) 2. T 3. .. -S ARGUMENT EIGHT Valid O / Invalid 0 1. ~(A · B) 2. :. -Av ~B ARGUMENT NINE Valid O / Invalid O 1. ~(A v B) 2. . -A v ~B
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- 30 Suppose a, b, and sum are int variables and c is a double variable. What value is assigned to each variable after each statement executes? Suppose a = 6, b = 3, and c = 2.2. (14) a b c sum sum = static_cast<int>(a + b + c); __ __ __ __ b += c * a; __ __ __ __ c -= a; __ __ __ __ a *= 2 * b - c; __ __ __ __(1) Prompt the user for a string that contains two strings separated by a comma. (1 pt) Examples of strings that can be accepted: Jill, Allen Jill , Allen Jill,Allen Ex: Enter input string:Jill, Allen (2) Print an error message if the input string does not contain a comma. Continue to prompt until a valid string is entered. Note: If the input contains a comma, then assume that the input also contains two strings. (2 pts)Ex: Enter input string:Jill AllenError: No comma in string. Enter input string:Jill, Allen (3) Extract the two words from the input string and remove any spaces. Store the strings in two separate variables and output the strings. (2 pts)Ex: Enter input string:Jill, AllenFirst word: JillSecond word: Allen (4) Using a loop, extend the program to handle multiple lines of input. Continue until the user enters q to quit. (2 pts)Ex: Enter input string: Jill, Allen First word: Jill Second word: Allen Enter input string: Golden , Monkey First word: Golden Second word:…Need help having code going past 21 hours on 24-hour clock and changing over to AM after 00:00! Thanks in advance #include <iostream>#include <ctime>//Had trouble with the variable localtime#pragma warning(disable : 4996) using namespace std; time_t now = time(0);tm* local = localtime(&now); int hour = local -> tm_hour;int minutes = local -> tm_min;int sec = local -> tm_sec; // Function to display the 12-hour clockvoid Clock12() { // Converts 24-hour clock to 12-hour if (hour > 12) { hour -= 12; } cout << "*****************************" << " " << "*****************************\n"; cout << "* 12-Hour Clock *" << " " << "* 24-Hour Clock *\n"; cout << "* " << (hour < 10 ? "0" : "") << hour << ":" << (minutes < 10 ? "0" : "") << minutes << ":" << (sec < 10 ? "0" : "") << sec <<…
- Assume the followingString s,t,h,a,n,e;int i;h = “Hello”;s = “How are you?”a = “abc”;n = null;e = “”;Give the values of the following expressions, or illegal1. h.length()2. h.substring(1)3. h.toUpperCase()4. h.toUpperCase().toLowerCase()5. h.indexOf("H")6. h.startsWith("ell")7. "Tomorrow".indexOf("o")8. "Tomorrow".indexOf("o", 3)9. "Tomorrow".lastIndexOf('o')10. "a = \"" + a + "\""11. (a.length() + a).startsWith("a")12. a.length() + a.startsWith("a")13. ">>>" + a.length() + a.startsWith("a")14. a.substring(1,3).equals("bc")15. a.substring(1,3) == "bc"16. "a".compareTo("c")17.…8. Write a program that allows the user to enter two integers and a character If the character is A, add the two integers If it is S, subtract the second integer from the first if it is M, multiply the integers Display the results of the arithmetic The following problems requires nested if-statements9. Write a console-based application that asks a user to enter an IQ score. If the score is a number less than 0 or greater than 200, issue an error message; otherwise, issue an “above average”, “average”, or “below average” message for scores over, at, or under 100, respectively.10. Write a console-based program that prompts a user for an hourly pay rate. If the user enters values less than $7.50 or greater than $49.99, prompt the user again. If the user enters an invalid value again, display an appropriate error message. If the user enters a valid value on either the first or second attempt, display the pay rate as well as the weekly rate, which is calculated as 40 times the hourly rate.…int a = 9; int c = 6; int d = 6; boolean m; if (a==c && c != d) { m = true}; What is the value of m? True False 6 9
- 2.15 LAB: Musical note frequencies On a piano, a key has a frequency, say f0. Each higher key (black or white) has a frequency of f0 * rn, where n is the distance (number of keys) from that key, and r is 2(1/12). Given an initial key frequency, output that frequency and the next 4 higher key frequencies. Output each floating-point value with two digits after the decimal point, which can be achieved as follows:print(f'{your_value1:.2f} {your_value2:.2f} {your_value3:.2f} {your_value4:.2f} {your_value5:.2f}')Print "user_num1 is negative." if user_num1 is less than 0. End with newline. Assign user_num2 with 1 if user_num2 is greater than 12. Otherwise, print "user_num2 is less than or equal to 12.". End with newline. My code: user_num1 = int(input())user_num2 = int(input()) if user_num1 < 0: print("user_num1 is negative.") if user_num2 > 12: user_num2 == 1 else: print("user_num2 is less than or equal to 12.") print('user_num2 is', user_num2) When the input is 0 and 13 my output for user_num2 is 13 and it should be 1. I don't know what I'm doing wrong.If, A = {3, 5, 7, 9} B = {2, 4, 6, 8, 10} C = {12, 14, 18, 20, 24} D = {21, 26, 31, 36} A. State whether TRUE or False: 1. 13 ∈ C 2. 6 ∉ A 3. 31 ∈ D 4. 20 ∉ B B. Fill in the blanks to make each statement true: 5.) 3 ∈ ___ 6.) 4 ___ B 7.) 26 ___ C 8.) 8 ∈ ___
- In Chapter 4, you created a program that generates a random number, allows a user to guess it, and displays a message indicating whether the guess is too low, too high, or correct. Now, create a modified program called GuessingGame2 in which the user can continue to enter values until the correct guess is made. After the user guesses correctly, display the number of guesses made. Recall that you can generate a random number whose value is at least min and less than max using the following statements: Random ranNumber = new Random(); int randomNumber; randomNumber = ranNumber.Next(min, max);If int x = 10;, int y = 7;, double z = 4.5;, and double w = 2.5;, evaluate each of the following statements, if possible. If it is not possible, state the reason. (3, 4) (x + y) % x x % y + w (z - y) / w (y + z) % x (x % y) * z x % y % 2 (x + y) % z (x % y + z) / wAssuming the following code: int x = myfunction1(); /* arbitrary value */ int y = myfunction2(); /* arbitrary value */ int z = myfunction3(); /* arbitrary value */ //convert to double double dx = (double) x; double dy = (double) y; double dz = (double) z; unsigned ux = x; unsigned uy = y; The following statement always evaluates to 1 (True or False): (dx + dy) + dz == dx + (dy + dz) True False
