article contained the following observations on degree of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range: 415 420 422 423 425 429 432 435 437 438 446 447 449 451 456 463 464 (c) Calculate a two-sided 95% confidence interval for true average degree of polymerization. (Round your answers to two decimal places.)
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An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:
415 | 420 | 422 | 423 | 425 | 429 | 432 | 435 | 437 |
438 | 446 | 447 | 449 | 451 | 456 | 463 | 464 |
(c) Calculate a two-sided 95% confidence interval for true average degree of polymerization. (Round your answers to two decimal places.)
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- An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range: 415 421 422 423 425 427 430 435 437 439 446 446 448 453 456 463 464 Calculate a two-sided 95% confidence interval for true average degree of polymerization. (Round your answers to two decimal places.) ( , )An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range: 415 421 422 423 425 427 430 435 437 439 446 446 448 453 456 463 464 Calculate a two-sided 95% confidence interval for true average degree of polymerization.A volumetric calcium analysis on triplicate samples of the blood serum of a patient believed to be suffering from a hyperparathyroid condition produced the following data: mmol Ca/L = 3.15, 3.25, 3.26. What is the 95% confidence interval for the mean of the data, assuming(a) No prior information about the precision of the analysis?(b) s → σ = 0.056 mmol Ca/L?
- In a study of maternal cigarette smoking and bone density in newborns, 77 infants of mothers who smoked had a mean bone mineral content of 0.098 g/cm3 (s1 = 0.026 g/cm3). The 161 infants whose mothers did not smoke had a mean bone mineral content of 0.095 g/cm3 (s2 = 0.025 g/cm3). Calculate the 95% confidence interval for µ1 - µ2During a routine check of the fluoride content of Gotham City's water supply, the given results were obtained from replicate analyses of a single sample: 0.513 mg/L0.513 mg/L , 0.487 mg/L0.487 mg/L , 0.511 mg/L0.511 mg/L , 0.489 mg/L0.489 mg/L , and 0.519 mg/L0.519 mg/L . Determine the mean and 90% confidence interval for the average fluoride concentration in this sample. Report the mean and the confidence interval with three significant figures.a researcher wishes to test the claim that,on average,more juveniles than adult are classified as missing person.Record for the first 5 years are shown in the table below: Juveniles 65513 65934 64213 61954 59167 Adults 31364 34478 36937 35946 38209 at the confidence interval of 90% is there enough evidence to support the claims?
- The drug Viagra became available in the U.S. in May 1988, in the wake of an advertising campaign that was unprecedented in scope and intensity. A Gallup poll found that by the end of the first week of May, 643 out of 1,005 adults were aware that Viagra was an impotency medication. a) Is the sample size large enough to compute a confidence interval for the proportion of adults who were aware that Viagra was an impotency medication after the first week of May? Yes, because more than 10 adults were not aware of Viagra Yes, because the sample size is greater than 30 Yes, because more than 10 adults were aware of Viagra Yes, because both np̂ and n(1-p̂) are greater than 10 b)Using the information from questions 1-3, suppose that p̂ is 0.40 and the standard error of p̂ is 0.10. Compute a 90% confidence interval for the proportion of adults that were aware of Viagra. (0.2355, 0.5645) (0.3, 0.5) (0.2355, 0.4) (0.3, 0.4)The ball corporations beverage can manufacturing plant in fort Atkinson, Wisconsin, uses mental supplier that provides mental with a known thickness standard deviation o=.000610 mm. Assume a random sample of 55 sheets of metal resulted in an x=.2839 mm the 90% confidence interval is from To ?In exploring possible sites for a convenience store in a large neighbourhood, the retail chain wants to know the proportion of ratepayers in favour of the proposal. If the estimate is required to be within 0.1 of the true proportion, would a random sample of size n = 100 from the council records be sufficient for a 95% confidence interval of this precision?
- A selected sample of ?n water specimens and estimate the mean daily rate of pollution produced by a mining operation. If the EPA wants a 99% confidence interval with a margin of error of 0.8 milligram per liter (mg/L), how many water specimens are required in the sample? Assume prior knowledge indicates that pollution readings in water samples taken during a day have been approximately normally distributed with a standard deviation of 4.5 (mg/L).Listed below are the amounts of net worth (in millions of dollars) of the ten wealthiest celebrities in a country. Construct a 99% confidence interval. What does the result tell us about the population of all celebrities? Do the data appear to be from a normally distributed population as required? 261198182170161153148148143143Consider the following results for independent random samples taken from two populations. Sample 1 Sample 2 n 1 = 10 n 2 = 30 x 1 = 22.5 x 2 = 20.3 s 1 = 2.1 s 2 = 4.9 What is the point estimate of the difference between the two population means (to 1 decimal)? What is the degrees of freedom for the t distribution (round down your answer to nearest whole number)? At 95% confidence, what is the margin of error (to 1 decimal)? What is the 95% confidence interval for the difference between the two population means (to 1 decimal)?