As a car accelerates, it does not accelerate at a constant rate; rather, the acceleration is variable. The quadratic function a(t) = −0.70t² + 1.44t + 10.44 describes the acceleration in seconds. Compute the average value of a(t) to estimate the average acceleration between t = 0 and t = 41.6 seconds. Round your answer to five decimal places.
As a car accelerates, it does not accelerate at a constant rate; rather, the acceleration is variable. The quadratic function a(t) = −0.70t² + 1.44t + 10.44 describes the acceleration in seconds. Compute the average value of a(t) to estimate the average acceleration between t = 0 and t = 41.6 seconds. Round your answer to five decimal places.
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter12: Quadratic Functions
Section12.8: Joint And Combined Variation
Problem 7P
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![As a car accelerates, it does not accelerate at a constant rate; rather, the acceleration is
variable. The quadratic function
a(t) = −0.70t² + 1.44t + 10.44
describes the acceleration in seconds. Compute the average value of a(t) to estimate the
average acceleration between t = 0 and t = 41.6 seconds. Round your answer to five decimal
places.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe804af83-6e9b-4519-aba3-6c7c3cd40e2f%2F5fa39d42-d433-4c20-9e93-567c6bfd801e%2F6tzm7in_processed.png&w=3840&q=75)
Transcribed Image Text:As a car accelerates, it does not accelerate at a constant rate; rather, the acceleration is
variable. The quadratic function
a(t) = −0.70t² + 1.44t + 10.44
describes the acceleration in seconds. Compute the average value of a(t) to estimate the
average acceleration between t = 0 and t = 41.6 seconds. Round your answer to five decimal
places.
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