DOO ALL PARTSS PLEASEEEEEE As a check on our work in part (a), notice that if we let a = 2, then f'(a) = f'(2) = Find the derivative of the function f(x) = x²SOLUTION(a) From this definition we have the following.f(2+h)-f(2)h(b)f'(2)=====f'(a):=====limh→0limh→0limh→0limh→0limh→0limh→0limh→0limh→0limh→0limh→04 +hf(a+h)-f(a)h23² + (1h7x + 8 at the numbers (a) 2 and (b) a.h7(2 + h) + 8 - [(2)² − 7(2) + 8]8 - [h147h + 8 + 2] ) - 760 +61 + 1] - (0²- 70 +7(a h) 8 [a² 8]hh7a - 7h + 8 - a² + 7a − 8

Answered: Image /qna-images/answer/ee41645d-9495-407d-aa68-bf7c65354b2e.jpg

Find the derivative of the function f(x) = x² − 7x + 8 at the numbers (a) 2 and (b) a. SOLUTION (a) From this definition we have the following. f(2 +h)-f(2) h (b) f'(2) = = lim = lim h→0 h→0 = lim h→0 = lim h→0 = lim h→0 = lim h→0 f'(a) lim = h→0 = lim h→0 lim h→0 = lim 4+ h→0 f(a+h)-f(a) h h a²+ h h 7(2+ h) + 8 +8] - 1 - [(2)²- - 7(2) + 8] h - 147h +8+2 h · 7(a + h) + 8 − [a² − 7a + 8] 8] – h - 7a − 7h + 8 − a² + 7a - 8

Find the derivative of the function f(x) = x² − 7x + 8 at the numbers (a) 2 and (b) a. SOLUTION (a) From this definition we have the following. f(2 +h)-f(2) h (b) f'(2) = = lim = lim h→0 h→0 = lim h→0 = lim h→0 = lim h→0 = lim h→0 f'(a) lim = h→0 = lim h→0 lim h→0 = lim 4+ h→0 f(a+h)-f(a) h h a²+ h h 7(2+ h) + 8 +8] - 1 - [(2)²- - 7(2) + 8] h - 147h +8+2 h · 7(a + h) + 8 − [a² − 7a + 8] 8] – h - 7a − 7h + 8 − a² + 7a - 8

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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