As per the trigonometric substitution x = 4 sin 0, the following triangle is obtained. sin 0 = X x² 16x² (16-x The indefinite integral is X cos = V 16- X 4 Rewrite the equation in terms of x. 1- 8 1/2 J dx = 8 arcsin x² 16x2 dx = X XV 16- X 4 + C
As per the trigonometric substitution x = 4 sin 0, the following triangle is obtained. sin 0 = X x² 16x² (16-x The indefinite integral is X cos = V 16- X 4 Rewrite the equation in terms of x. 1- 8 1/2 J dx = 8 arcsin x² 16x2 dx = X XV 16- X 4 + C
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.4: Multiple-angle Formulas
Problem 70E
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