As shown in the figure, a heavy rock is shot upward from the edge of a vertical cliff. It leaves the edge of the cliff with an initial velocity of v, directed at 0 from the vertical and experiences no appreciable air resistance as it travels. The rock lands at a distance of 3.40 m from the base of the cliff as shown. Solve in terms of the provided variables plus other known constants. How high is the cliff? h= ? 3.40 m Upload your symbolic solution here. Make sure you show all your work clearly. Upload Choose a File Question 5 Based on your equations for the above problem, solve for the cliff's height (in meters) when the rock has an initial velocity of 4.37 m/s at an angle of 82.74 with respect to the vertical. The range is 3.40 m as shown in the figure. (Enter a number only. No units!)

As shown in the figure, a heavy rock is shot upward from the edge of a vertical cliff. It leaves the edge of the cliff with an initial velocity of v, directed at 0 from the vertical and experiences no appreciable air resistance as it travels. The rock lands at a distance of 3.40 m from the base of the cliff as shown. Solve in terms of the provided variables plus other known constants. How high is the cliff? h= ? 3.40 m Upload your symbolic solution here. Make sure you show all your work clearly. Upload Choose a File Question 5 Based on your equations for the above problem, solve for the cliff's height (in meters) when the rock has an initial velocity of 4.37 m/s at an angle of 82.74 with respect to the vertical. The range is 3.40 m as shown in the figure. (Enter a number only. No units!)