asc^ (I+tanx) dx cOs ²x

Q: Differentiate (sinx)2(sin-1x)2

A:

Q: sinx-cosx dx ex+ Sinx

A:

Q: sec²(,Æ) 24. dx

A:

Q: 2 cosx+3 cosx=2, 0Sx<27

A:

Q: السؤال 3 -Sec2 (). dx tan (5). · dz O ). de tan tan . da O ). dz O tan

A:

Q: Differentiate y=(1-cosx)/sinx

A:

Q: (sinºx sec²x csc³x + sin*4x).dx

A: Given an integral. We need to evaluate it.

Q: Differentiate sin x +1

A:

Q: 12.y = sin(tanx) 13.y = 2sinxcosx cosx 14.y = x2 tanx 15.y = sinx

A: We have to find derivative

Q: 1 sec²x + tanx %3D tanx tanx

A:

Q: Period of y = sin 3x

A: Given, y=sin(3x) ∴ Frequency in radians, ω=3 ∴ Frequency in Hz, f = ω2π =&gt; f = 32π Time period, T…

Q: Transforming dx using miscellaneous substitution will yield to secx + 1

A:

Q: Se-*cos(5x) dx

A: Given : ∫ e−xcos(5x)dx

Q: Integrate dx/(sinx+cosx)

A:

Q: integrate sin(x)

A:

Q: coshx 5) dx ++sinh²x

A: Some of the important formulas  d(sinh x)dx=cosh x ∫1a2+x2 dx=ln x+a2+x2 +C

Q: Differentiate y=(1-cosx)/sin2x

A:

Q: sec2 3x dx J tan²3x-3 tan3x+2

A:

Q: Sinx dx Cosx/1-Cos²x S 2*dx

A:

Q: Evaluate tan (7x+1) sec³(7x+1) dx .

A:

Q: Differentiate y=(sinx)2(sin-1x)2

A:

Q: - Se-3x sin 4x dx

A:

Q: | sin³(18x) dx =

A:

Q: Determine (tanx sec' x dx

A: We will evaluate the integral.     We know  sec2x - tan2 x = 1            implie, sec2x = 1+ tan2 x

Q: Integrate  1/sinx

A:

Q: secx d) tanx + cotx sinx

A: see below the calculation and answer

Q: tan (2x)sec (2x)dx 3

A:

Q: cotx/5+tanx 7. S dx cotx-sinxcosx

A: I answered as per guideline of bartleby..kindly repost another one ...thankyou

Q: Evaluate tan (3x+1) sec³(3x+1) dx

A:

Q: 2.) (cotx + tanx) ² dx

A:

Q: ) Evaluate cosx sinx V1 – sin4x dx.

A: Use substitution method to solve this

Q: Solve (cosx)dy = (sinx)dx

A: The objective is to solve the expression cosxdy=sinxdx

Q: (5x+sin3(4x) + sin(4x³)) dx

A: use differentiation for finding the solution.

Q: cosx = secx-sinx tanx %3D

A:

Q: Integrate  tan4xsec2x dx

A:

Q: | sin-1 3x dx

A:

Q: cos 6x cos 2x dx

A:

Q: -22 (sinhx+coshx) dx

A:

Q: Find Dx (sin4 x).

A: we have to find the value of Dxsin4x

Q: tantx + CosX-Stcx = SeC %3D COSX

A:

Q: (cotx + tanx)² dx 3 4

A:

Q: dx sec5x(3+sin5х)

A:

Q: sin (2x)dz

A: Given ∫e6xsin2xdx

Q: Differentiate.   y =  Sin -1(ex)

A:

Q: sinx dx (cosx)2+cosx-2

A: Use substitution method:  Substitute cosx =t

Q: Find ∫sec4 3x tan3 3x dx.

A: ∫xndx=xn+1n+1+C

Q: fcox In(sinx) dx= fu du cotx In(sinx) dx = u du

A: In this question we substitute  u=lnsinx .

Q: 9 coshx - 5 sinhx 15 %3D

A: To solve  9coshx-5sinhx=15

Q: Sec tan (5x) dx

A:

Q: Sinx tanx t COSX = Secx 11

A: