Operating system ,Please write the code in C language. Use hardware mechanism test and set or swap to solve synchronization for lab 4 exerciseLab 4 exercise :#include #include #include long long sum=0, num32000000;pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER;void *mySumFun (void *vargp)int step=* (int *) vargp;for (int i-0;i

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Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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MATLAB code that matches the value from two variables within certain parameters. It can only use for or while loops, conditional statements, Boolean logic, or logical operators to find a match between the two inputs. For example, one input can be x = 42 and b = 61, and these two inputs would yield a match. The first condition that needs to be met to obtain a match is that x can be equal to 2, 21, 40, and 59. Variable b must also be equal to these values to have a match. The values for x have to increase by one for every loop iteration until the final values for x are: 19, 38, 57, and 76. So the matching has to take place within the same values for x as for b and within those range of values described. If a match is found then set b = d.
A hardware implementation is required for executing the following equations, draw proper diagrams to complete your results. 1- x+y+z+a.b : R3 <- R4-R52- a.c.b+d : R3 <- R4+R6
Each process Pi maintains a boolean array, dependenti , where dependenti(j) is true only if Pi knows that Pj is dependent on it. Initially, dependenti(j) is false for all i and j.
Determine the complexity and count the primitive operation. Show your solution on counting and adding the sum of primitives public static void main(String[] args) {Scanner scanner = new Scanner(System.in);System.out.print("Enter a number for count:");int n = scanner.nextInt();for(int i = 1; i <= n; i++){System.out.print(printFibonacci(i) + " ");}input.close();private static int printFibonacci(int cNumber){if(cNumber == 1 || cNumber == 2){return 1;}return printFibonacci(cNumber - 1) + printFibonacci(cNumber - 2);}}
There are many algorithms presented in this text that would lend themselves to beincluded as subprograms in the utils.asm file. Implement some or all of the followinginto the utils.asm file, properly documenting them, and include programs to test them.a. NOR subprogram - take two input parameters, and return the NOR operation onthose two parameter.b. NAND- take two input parameters, and return the NAND operation on those twoparameter.c. NOT- take one input parameters, and return the NOT operation on that parameter.d. Mult4 - take an input parameter, and return that parameter multiplied by 4using only shift and add operations.e. Mult10 - take an input parameter, and return that parameter multiplied by 10using only shift and add operations.f. Swap- take two input parameters, swap them using only the XOR operation.g. RightCircularShift - take an input parameter, and return two values. The firstis the value that has been shifted 1 bit using a right circular shift, and the second isthe…
Convert this C code into MIPS Assembly Language #define WINNER_NONE 0 int check_winner(void) { for (int row = 0; row < board_height; row++) { for (int col = 0; col < board_width; col++) { int check; check = check_line(row, col, 1, 0); if (check != WINNER_NONE) return check; check = check_line(row, col, 0, 1); if (check != WINNER_NONE) return check; check = check_line(row, col, 1, 1); if (check != WINNER_NONE) return check; check = check_line(row, col, 1, -1); if (check != WINNER_NONE) return check; } } return WINNER_NONE; } int check_winner(void) { for (int row = 0; row < board_height; row++) { for (int col = 0; col < board_width; col++) { int check; check = check_line(row, col, 1, 0); if (check != WINNER_NONE) return check; check = check_line(row, col, 0, 1); if (check != WINNER_NONE) return check; check = check_line(row, col, 1, 1); if (check != WINNER_NONE) return check; check = check_line(row, col, 1, -1); if (check != WINNER_NONE) return check; } }…
Good afternoon,Would it be possible for someone to help me to correct this code in matlab unfortunately it is not working a small error appears and make some changes as : This is an multi objective genetic algorithm to optimize an turbojet two spool afterburner. % Define your own constraint functions as a cell arraymyCons = {@(x) f>=1, @(x) Fn>=1, @(x) m0>=1, @(x) p3>=1, @(x) Tpz>=1, @(x) o>=1, @(x) t>=1, @(x) aa>=1, @(x) WTO>=1, @(x) WLanding>=1, @(x) WF>=1, @(x) WE>=1, @(x) WPL>=1, @(x) WC>=1, @(x) M>=1, @(x) Fab>=1, @(x) V9>=1, @(x) V0>=1, @(x) QR>=1, @(x) NB>=1, @(x) T1>=1, @(x) T0>=1, @(x) L>=1, @(x) p>=1, @(x) V>=1, @(x) A>=1, @(x) bw>=1, @(x) sw>=1, @(x) WZF>=1, @(x) b>=1, @(x) cr>=1, @(x) ct>=1, @(x) WS>=1, @(x) RC>=1, @(x) l>=1, @(x) m>=1, @(x) W0>=1, @(x) VH>=1, @(x) VS>=1, @(x) VS1>=1}; confun = @(x) cellfun(@(f) f(x), myCons); % Evaluate all constraint…
implement a function for finding the nth Fibonacci number using the MIPS assembly language. Following gives the definition of the Fibonacci Sequence.Let F be the Fibonacci function:F(0) = 0F(1) = 1For n > 1 F(n) = F(n-1) + F(n-2)Example Output of Execution:Enter the sequence number: 6F(6) = 8 A - Loop ImplementationIn a file named FiboLoop.asm, implement the above function using a loop. B - Recursive ImplementationIn a file named FiboRec.asm, implement the above function using a loop.
Cellular Automata perform distributed computation through the iteration of (relatively) simple logic within individual cells in an array. The following table defines the logic for a one-dimensional Cellular Automaton (CA): Neighbourhood: 000 001 010 011 100 101 110 111 Output bit: 0 1 1 1 0 1 1 0 a) Show the states of each of the cells in a ten-cell, one-dimensional CA from the given start states, following the above rule for three update cycles: 0010111010
Generate a graph of performance improvement for code below. Tip: Figure 5.17 in the textbook provides an example of a graph depicting performance improvements associated with loop unrolling. code: //normal code int main() { int n, sum=0; n=50; int a[50]; { for(int i=0; i<n; i++) { sum= sum +a[i]; } printf("sum is %d", sum); return 0; } //with unrolling int main() { int n, sum=0; n=50; int a[50] for(int i=0; i<n; i+=10) { scanf("%d", &a[i]); } sum= sum + a[0]; sum= sum + a[1]; sum= sum + a[2]; sum= sum + a[3]; sum= sum + a[4]; sum= sum + a[5]; sum= sum + a[6]; sum= sum + a[7]; sum= sum + a[8]; sum= sum + a[9]; printf("sum is %d", sum); return 0; }
explain these python codes with comments , explain briefly >>> for iteration_num in range(5): ... correct_answers = 0 ... for idx, sample in enumerate(sample_data): ... input_vector = np.array(sample) ... weights = np.array(weights) ... activation_level = np.dot(input_vector, weights) +\ ... (bias_weight * 1) ... if activation_level > activation_threshold: ... perceptron_output = 1 ... else: ... perceptron_output = 0 ... if perceptron_output == expected_results[idx]: ... correct_answers += 1 ... new_weights = [] ... for i, x in enumerate(sample): ... new_weights.append(weights[i] + (expected_results[idx] -\ ... perceptron_output) * x) ... bias_weight = bias_weight + ((expected_results[idx] -\ ... perceptron_output) * 1) ... weights = np.array(new_weights) ... print('{} correct answers out of 4, for iteration {}'\ ... .format(correct_answers, iteration_num)) 3 correct answers out of 4, for iteration 0 2 correct answers out of 4, for iteration 1 3 correct answers out of 4,…
#include <stdio.h>int main (){ unsigned int x = 0x76543210; char *c = (char*) &x; printf ("*c is: 0x%x\n", *c); if (*c == 0x10) { printf ("Architecture is little endian. \n"); } else { printf ("Architecture is big endian. \n"); } return 0;} void printBin(int n){ unsigned i; for (i = 1 << 31; i > 0; i = i / 2) (n & i) ? printf("1") : printf("0");} int main(void){ printBin(17); printf("\n"); printBin(4);}