Assume that Laguna Lake has a volume of 480km^3 and that its rate of inflow (from Lake Huron) and outflow (to Lake Ontario) are both 350km^3 per year. Suppose that at time t = 0 (years), the pollutant concentration of Laguna Lake - caused by past industrial pollution that has now been ordered to cease - is five times that of Pasig Lake. If the outflow henceforth is perfectly mixed lake water, how long will it take to reduce the pollution concentration in Laguna Lake to twice that of Pasig Lake? * O 1.901 years = (48/35)In2 %3D O 1.901 years = (48/35)In4 0.505 years = (48/35)In4 O 0.505 years = (48/35)In2 %3D

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Assume that Laguna Lake has a volume of 480km^3 and that its rate of
inflow (from Lake Huron) and outflow (to Lake Ontario) are both
350km^3 per year. Suppose that at time t = 0 (years), the pollutant
concentration of Laguna Lake - caused by past industrial pollution that
has now been ordered to cease - is five times that of Pasig Lake. If the
outflow henceforth is perfectly mixed lake water, how long will it take
to reduce the pollution concentration in Laguna Lake to twice that of
Pasig Lake? *
O 1.901 years = (48/35)In2
%3D
O 1.901 years = (48/35)In4
0.505 years = (48/35)In4
O 0.505 years = (48/35)In2
%3D
Transcribed Image Text:Assume that Laguna Lake has a volume of 480km^3 and that its rate of inflow (from Lake Huron) and outflow (to Lake Ontario) are both 350km^3 per year. Suppose that at time t = 0 (years), the pollutant concentration of Laguna Lake - caused by past industrial pollution that has now been ordered to cease - is five times that of Pasig Lake. If the outflow henceforth is perfectly mixed lake water, how long will it take to reduce the pollution concentration in Laguna Lake to twice that of Pasig Lake? * O 1.901 years = (48/35)In2 %3D O 1.901 years = (48/35)In4 0.505 years = (48/35)In4 O 0.505 years = (48/35)In2 %3D
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