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Assume that the address for integer i is baseaddress+4 and the address for a[0] is baseaddress+8. Assume that the baseaddress is stored in Sgp. The code initializes i to 0; it then iterates from i=0 to i-9, setting a[i] 32i in each iteration. To make your code efficient, i must be loaded into a register at the start, and it must be updated in memory only after you've finished the for loop. for (i=0; i<10; i++) a[i] = 32*i; !!

Assume that the address for integer i is baseaddress+4 and the address for a[0] is baseaddress+8. Assume that the baseaddress is stored in Sgp. The code initializes i to 0; it then iterates from i=0 to i-9, setting a[i] 32i in each iteration. To make your code efficient, i must be loaded into a register at the start, and it must be updated in memory only after you've finished the for loop. for (i=0; i<10; i++) a[i] = 32*i; !!

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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6. Write the MIPS assembly code that corresponds to the pseudo code below. Assume that the address for integer i is baseaddress+4 and the address for a[0] is baseaddress+8. Assume that the baseaddress is stored in Sgp. The code initializes i to 0; it then iterates from i=0 to i=9, setting aſi] = 32i in each iteration. To make your code efficient, i must be loaded into a register at the start, and it must be updated in memory only after you've finished the for loop. for (i-0; i<10; i++) a[i] = 32*i;
Transcribed Image Text:6. Write the MIPS assembly code that corresponds to the pseudo code below. Assume that the address for integer i is baseaddress+4 and the address for a[0] is baseaddress+8. Assume that the baseaddress is stored in Sgp. The code initializes i to 0; it then iterates from i=0 to i=9, setting aſi] = 32i in each iteration. To make your code efficient, i must be loaded into a register at the start, and it must be updated in memory only after you've finished the for loop. for (i-0; i<10; i++) a[i] = 32*i;
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