Assuming the char data type uses 1 byte of memory, how many bytes do thefollowing literals use?'Q'"Q""Sales"'\n'
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Assuming the char data type uses 1 byte of memory, how many bytes do the
following literals use?
'Q'
"Q"
"Sales"
'\n'
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Solved in 2 steps
- The following program or program segment has errors. Find as many as you can. char numeric[5]; int x = 123; numeric = atoi(x);Assuming the char data type uses 1 byte of memory, how many bytes do each of the following literals use? 'Q' "Q" "Sales" '\n'def evalsum(s): """Returns a string encoding a sum expression as a value.""" evalsum: This function should accept a string encoding decimal numbers, separated by whitespace and by + and - operators, and should return None if invalid or the sum as a python float. For example, evalsum("1+2.2-3.141592") should return -0.5840800.... An input string-encoded number can be integral or not, can have preceding or trailing zeros or not, and can begin with a period, but cannot end with a period. Hint: try using re.match to match a prefix of the string in a loop, removing that prefix at each iteration.
- Complete this code using python language #Write the conditions to check if anyone has won the game. This function will be called from the placeCharacter function. # r : In which row the current character was placed# c : In which column the current character was placed#returned value: True if anyone has won;Otherwise Flasedef checkBoard(r,c):#Write your code here #Write the necessary code to put the "char" in proper position of the board and check if anyone has won.#pos : The position that has been given by the player as input.#char : The character representing the player. It can be X or O.#count: It represents the number of turns. It can be from 0 to 8.#returned value: True if anyone has won;Otherwise Flasedef placeCharacter(pos,char,count):#Write your code heredef gameInitialization():global player1,player2player1 = input("Enter player 1's name:")player2 = input("Enter player 2's name:")print(f"{player1}, your character is X")print(f"{player2}, your character is O")def…An alternative way to write A[0] is a. &A b. A.0 c. *A[0] d. *Adraw flow char for this code is easy 2 #include 3- int main() { 4 char c; 5 6 7 8 9 ▾ 10 11 12 13 14 15 16 17 18 19 20 21 22 23 } printf("Enter a character: "); scanf("%c", &c); // Convert Lowercase to uppercase and vice versa if (c >= 'a' && c = 'A' && c <= 'Z') { c = c + 32; // Convert uppercase to Lowercase } 2. Write a C program that ask the user to enter a character then the program will print the input character and the next characters in ascending order up to character 'Z'. (Note: if the user enters lower case character, the program will print lower case character and vice versa) } // Print the character and subsequent characters in ascending order while (c <= 'Z') { printf("%c ", c); C++; 32; // Convert Lowercase to uppercase printf("\n"); return 0; Enter a character: v V W X Y Z input
- Write code so that you take three integers a,b, and c display a^b - c.(Numerical) Using the srand() and rand() C++ library functions, fill an array of 1000 floating-point numbers with random numbers that have been scaled to the range 1 to 100. Then determine and display the number of random numbers having values between 1 and 50 and the number having values greater than 50. What do you expect the output counts to be?Vehicle Displacement You are given the velocity of shuttle traveling in a straight line as a series of data points. Write a program that computes the position (displacement) of the shuttle along this line at the time of the final data point The input is given vis standard input in the following format number of data points (0 < 65,535) on its own in • It pairs of data points, each on their own line, consisting of two integers separated by a ungle comma The first number represents the time in seconds (065535), and the second represents velocity in meters per second (4 v). Time is strictly increasing and velocity is constant between data points. The vehicle position and velocity both start at 0 May shuttles can drive in either direction, and in an added bit of realm the data points are speed-limited to about 25 mph in forward and 10 mph in reverse. However, in a reduced bit of realsm, the problem does imply that shuttles can change velocity instantaneously The output should be a single…