Assuming we have found the position in the array s containing the same value stored in the variable e, we now wish to write a code that deletes that number from the array, but retains the ascending order of all remaining integers in the array. For example, given: s = (2, 4, 6, '8, 0}; e - 6; pos = 2; The desired outcome is to remove the 6 from 2 to give: s = (2, 4, 8, 0, 0}; Consider the following skeleton code, where xxXXxx is substitute for the correct line of code: do { ++pos; XXXXXX; } while (s[posl!=0); The correct replacement for xxxxx is: s[pos+1] = s[pos); O sĺpos] = s[pos+1]); O sĺpos] = s[pos-1]; O sĺpos-1] = s[pos];

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Assuming we have found the position in the array s containing the same value stored in the variable e,
we now wish to write a code that deletes that number from the array, but retains the ascending order of
all remaining integers in the array. For example, given:
s = (2, 4, 6, '8, 0};
e = 6;
pos = 2;
The desired outcome is to remove the 6 from 2 to give:
s = (2, 4, 8, 0, 0};
Consider the following skeleton code, where xx is substitute for the correct line of code:
do {
++pos;
XXXXXX;
} while (s[pos]!=0);
The correct replacement for xxxxx is:
sĺpos+1] = s[pos);
s[pos] = s[pos+1];
s[pos] = s[pos-1];
s[pos-1] = s[pos];
Transcribed Image Text:Assuming we have found the position in the array s containing the same value stored in the variable e, we now wish to write a code that deletes that number from the array, but retains the ascending order of all remaining integers in the array. For example, given: s = (2, 4, 6, '8, 0}; e = 6; pos = 2; The desired outcome is to remove the 6 from 2 to give: s = (2, 4, 8, 0, 0}; Consider the following skeleton code, where xx is substitute for the correct line of code: do { ++pos; XXXXXX; } while (s[pos]!=0); The correct replacement for xxxxx is: sĺpos+1] = s[pos); s[pos] = s[pos+1]; s[pos] = s[pos-1]; s[pos-1] = s[pos];
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